Question

How do you simplify\[\frac{(x-(1+\sqrt{2}))(x-(1-\sqrt{2})) }{(x-3)(x-1)}\]to find the value of x?

Answer 1

@bibby

Answer 2

Hey Oakley~

Answer 3

ew, work. let me try some stuff

Answer 4

Lol alright

Answer 5

this'd be a lot easier if it were a+b(a-b) form, hmm

Answer 6

Heh. :p

Answer 7

and combine like terms, let me double check

Answer 8

wut.

Answer 9

as in \(-2x -2x\sqrt2\)

Answer 10

brb looking over all the answers
sorry I d/c'd

Answer 11

I think I messed something up, let me work it out onpaper

Answer 12

okay

Answer 13

yeah I flubbed up

Answer 14

you said you want to find the value of x?
are you sure because i don't see any equality sign
you mean simplify

Answer 15

Nope, solve for x

Answer 16

I didn't write teh denominator to save space

Answer 17

Thanks Oakley

Answer 18

the point remains there's nothing to solve for. we simplified the thing

Answer 19

oh you want the original equation then?

Answer 20

that's not the original

Answer 21

this is just a place where I got stuck after following a tutor's instructions, but the tutor isn't here so

Answer 22

here how i would do it:
\[\large \frac{[(x-1)+\sqrt{2}][(x-1)-\sqrt{2}]}{(x-3)(x-1)}=\frac{(x-1)^2-2}{(x-3)(x-1)}\]

Answer 23

and carry the simplification

Answer 24

I'm gonna kill myself

Answer 25

rofl, thanks

Answer 26

welcome:)
you did good too

Answer 27

in case you are wondering where i did come up with that
it is just grouping things

Answer 28

I think I'm good, thanks.

Answer 29

welcome :)

Answer 30

...I wonder if anyone noticed?

Also - I should know this by now but I don't. I feel dumb. u_u

Answer 31

in your comment above you said this is not the original question
so where the rest of the question?

Answer 32

That wasn't my comment...? :p

Answer 33

It's in a packet that I will find later

Answer 34

it was the poster's comment!!

Answer 35

Anyway, brb. Finding the packet

Answer 36

no i just realized, perhaps that was your curiosity when you asked heheh

Answer 37

nvm haha

Answer 38

Oh I am gonna hate typing this.

Answer 39

\[\frac{4}{x^{2}-2x-3}\ge\frac{x}{x-3}-\frac{1}{x+1}\text{, solve for }x\]

Answer 40

what do you think?

Answer 41

What does that mean? e_e

Answer 42

it means what are your thought on how to solve that?

Answer 43

Uh... dunno

Answer 44

I mean I did it but I got stuck somewhere along the line

Answer 45

\[\frac{4}{x^{2}-2x-3}\ge\frac{x(x+1)-(x-3)}{x^{2}-2x-3}\]

Answer 46

the denominator on the left had side factor to (x-3)(x+1) see if that helps

Answer 47

\[\frac{4}{x^{2}-2x-3}\ge\frac{x^{2}-3x+3}{x^{2}-2x-3}\]

Answer 48

so...

Answer 49

how about you get rid of that same denominator can we do that

Answer 50

but we have to be careful of the sign

Answer 51

\[\text{Hypothesized solution }0\ge\frac{x^{2}-2x-1}{x^{2}-2x-3}\text{ after shifting the left side over to the right}\]

Answer 52

so yeah basically went through all those steps and then got stuck

Answer 53

nvm i gotta go
but that solution of urs is interesting how did you do that

Answer 54

do you have the answer? i just have x = 0 or <1

Answer 55

The tutor gave me the hypothesized solution @xapproachesinfinity

Answer 56

It does make logical sense but I get to a certain standpoint and I get stuck.