Question

What is the standard form of the equation of a circle with its center at (2, -3) and passing through the point (-2, 0)?

(x - 2)2^ + (y + 3)2^ = 5

(x + 2)2^ + (y - 3)2^ = 25

(x - 2)2^ + (y + 3)2^ = 25

(x - 2)2^ - (y + 3)2^ = 5

Answer 1

@Sasarapony123

Answer 2

@shyboo1998

Answer 3

@K_V8

Answer 4

ok so whats the question

Answer 5

^^^

Answer 6

@Sasarapony123 HELP

Answer 7

uh my math isn't that advanced yet sorry

Answer 8

ill try my best though

Answer 9

Okay

Answer 10

I only have 15 mins left of class

Answer 11

have to go

Answer 12

u have to go?

Answer 13

A circle is described by the equation (x−12)2+(y−32)2=49. What are the cordinates for the center of the circle and the length of the radius?

Answer 14

(-12,-32), 23units
(-12,-32), 49units

(12,32), 49units

(12,32), 23units

Answer 15

Try it and ill be back tomorrow

Answer 16

the ????????? are subtraction

Answer 17

What is the general form of the equation for the given circle centered at O(0, 0)?

x2 + y2 + 41 = 0

x2 + y2 − 41 = 0
x2 + y2 + x + y − 41 = 0

x2 + y2 + x − y − 41 = 0

Answer 18

What is the general form of the equation of a circle with center at (a, b) and radius of length m?

x2 + y2 − 2ax − 2by + (a2 + b2 − m2) = 0

x2 + y2 + 2ax + 2by + (a2 + b2 − m2) = 0

x2 + y2 − 2ax − 2by + (a + b − m2) = 0

x2 + y2 + 2ax + 2by + a2 + b2 = -m2