Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (vshiroky):

Solve by graphing

OpenStudy (vshiroky):

OpenStudy (misty1212):

HI!!

OpenStudy (misty1212):

\[x-y=-2\\ x+y=4\] if you add them you get \[2x=2\] and so \(x=1\)

OpenStudy (vshiroky):

That doesn't make sense to me still. I have to have 2 ordered pairs.

OpenStudy (misty1212):

yes, i know you need two numbers \((x,y)\) but if \(x=1\) and \(x+y=4\) then you know what \(y\) is right? you have \(1+y=4\) so that means \(y=3\)

OpenStudy (vshiroky):

ok...

OpenStudy (misty1212):

the ordered pair is \((1,3)\) and you can check it is right, because \(1-3=-2\) and \(1+3=4\) as required

OpenStudy (misty1212):

but you don't seem convinced huh?

OpenStudy (vshiroky):

No I get that now, but when I graph it how do I know where to put my 2nd point?

OpenStudy (misty1212):

graphing is really a bad way to do this do you actually have to graph both lines?

OpenStudy (vshiroky):

I do

OpenStudy (misty1212):

ok that sucks no matter you are going to have to graph two different lines, not one line they will meet at \((1,3)\) you can plot some points for \(x-y=-2\) for example you can plot \((0,2)\) and \((-2,0)\) and connect the dots

OpenStudy (misty1212):

|dw:1421956739985:dw|

OpenStudy (misty1212):

then you have to graph the line \(x+y=4\) again by plotting two points, say \((0,4)\)and \((4,0)\)

OpenStudy (vshiroky):

Thank you. I do not like these lol I still have like 8 more!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!