Question

How do I solve this math problem? Please don't give me the answer.

3+p/3 - 4p=1 - p+7/2

Answer 1

still need help?

Answer 2

Yes please!!!!!!

Answer 3

\(\dfrac{3+p}{3}-4p =1-\dfrac{p+7}{2}\), right?

Answer 4

yes

Answer 5

When I multiply and then divide a term by the same number, that term doesn't change, right? so, if I do something like this, can you get it? (Nothing change)
\(\dfrac{3+p}{3}\color{blue}{\dfrac{2}{2}}-4p\color{red}{\dfrac{6}{6}} =1\color{green}{\dfrac{6}{6}}-\dfrac{p+7}{2}\color{purple}{\dfrac{3}{3}}\)

Answer 6

I kind of get what you are saying

Answer 7

But where did you get those numbers from?

Answer 8

I did it to get the same denominator for all terms. It comes from the available denominator 3 and 2, then the same denominator is 6. Therefore, the first term \(\dfrac{3+p}{3}\) need 2 to get 6 (when multiplying)

Answer 9

That makes more sense

Answer 10

the second term is 4p, hence the denominator is 1, then we need *6 to get common denominator, ok?

Answer 11

Ok

Answer 12

the same reason with the right hand side, ok?

Answer 13

Ok

Answer 14

Now, all are the same denominator, we just distribute and combine like terms:
\(\dfrac{(3+p)2}{6}-\dfrac{6(4p)}{6} =\dfrac{6}{6}-\dfrac{(p+7)3}{6}\) ok?

Answer 15

\(\dfrac{6+2p-24p}{6}=\dfrac{6-(3p+21)}{6}\\\dfrac{6-22p}{6}=\dfrac{3p-15}{6}\)
got me so far?

Answer 16

Not finish yet, but you need understand before moving on. Just few more steps and we are done.

Answer 17

Yes I understand

Answer 18

Sorry for the late reply