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thanks
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\(tan (\dfrac{\pi}{4})=?\)
yep
wait lol check the pic
=? not yep :)
hey, should remember this "golden " point. pi/4 is a special point whose cos = sin, and tan =1
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oh, no, it is not d)
\(cos^{-1}(tan (pi/4)) = cos^{-1}(1)\)
and we know that \(cos^{-1}(a) = \theta\) implies that \(cos \theta = a\)
you have \(cos^{-1}(1) = ? \) that is \(1= cos ?\) when ? = 0, cos 0 =1, right?
yea but its not a choice
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yes, you are correct, like I deal with myself when noone make a conversation with me
how about c) which says 0??
yea lol forgot about that haha thanks
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