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Consider the function: f(x) =3/4x^4 - x^3 -3x^2 + 6x Determine the interval(s) where f(x) is increasing (if any) and the interval(s) where f(x) is decreasing (if any).
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@nincompoop
\[f(x)=\frac{3}{4}x^4-x^3-3x^2+6x \\ \text{ First step is to differentiate }\]
Then find when f'=0
Then we will draw a number line and test intervals.
Can you find f'?
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f' = 3x^3 -3x^2 -6x +6
ok and then we need to find when f'=0
it looks like you can factor by grouping if i'm not mistaken
3(x-1)(x^2-2)
\[f'(x)=3x^2(x-1)-6(x-1) \\ f'(x)=(x-1)(3x^2-6)\] now set both factors equal to zero and solve to find when f'=0
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yes that factorization works awesome too
I left my 3's either way
x = 1 and x =+- sqrt2
|dw:1421968754166:dw| we have 4 intervals to check
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