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Mathematics 18 Online
OpenStudy (anonymous):

f(g(x)) type question

OpenStudy (anonymous):

OpenStudy (anonymous):

What did I do wrong?

OpenStudy (solomonzelman):

you know that to verify that \(\large\color{slate}{ f^{-1}(x) }\) is indeed the inverse of \(\large\color{slate}{ f(x) }\), you would need to show that: \(\large\color{black}{ \color{red}{f(}\color{blue}{f^{-1}(x)}\color{red}{)} =\color{blue}{f^{-1}(\color{red}{f(x)})} }\)

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

The question is asking for me to show that f(g(x)) and g(f(x)) both equal x I think. Can I just show that they equal each other?

OpenStudy (solomonzelman):

I think it would be the same exact thing.

OpenStudy (solomonzelman):

I mean if each of them is equal to x, then they are equal to each other, but I think you actually need to show that each is equal to x.

OpenStudy (solomonzelman):

The idea is to show that they reflect each other over the graph of x, saying over a line of y=x.

OpenStudy (jdoe0001):

swagmaster47 is not asking if both are equal is asking if they're inverse of each other

OpenStudy (jdoe0001):

and you'd do it as SolomonZelman said by getting of f(g(x)), you should end up with "x" and the other way around

OpenStudy (jdoe0001):

on the 3rd line, your multiplication on the numerator above, went awry \(\bf f(g(x))=\cfrac{\frac{-3x-7}{x-1}-7} {\frac{-3x-7}{x-1}+3}\implies \cfrac{\frac{-3x-7+[(x-1)\cdot -7]}{\cancel{ x-1}}}{\frac{-3x-7+[3(x-1)]}{\cancel{ x-1}}} \\ \quad \\ \implies \cfrac{-3x-7-7x+7}{-3x-7+3x-3}\implies ?\)

OpenStudy (anonymous):

-10x/10 then x

OpenStudy (anonymous):

I mean -10x/-10

OpenStudy (anonymous):

and then when I get to g(f(x)) = (-3( (x-7)/(x + 3) )-7)/( ( (x-7)/(x + 3) )-1) I multiply by (x+3)/(x+3) ?

OpenStudy (anonymous):

would that look like (-3( (x-7) )-7(x+3) )/( (x-7) -(x+3) )

OpenStudy (jdoe0001):

well... those (x-3) cancel out because is a division of fractions and \(\bf \cfrac{\frac{a}{b}}{\frac{c}{{\color{blue}{ d}}}}\implies \cfrac{a}{b}\cdot \cfrac{{\color{blue}{ d}}}{c}\) would cancel each otehr out in the multiplication

OpenStudy (jdoe0001):

hmm x+3 I meant.. anyhow, so they cancel each other out

OpenStudy (anonymous):

Oh, so it looks like this? (-3( (x-7) - 7)/( x - 7 ) - 1)

OpenStudy (anonymous):

I would just remove b and d in your diagram right?

OpenStudy (anonymous):

If b = d

OpenStudy (jdoe0001):

yes, because in this case b = d yes

OpenStudy (anonymous):

Ok I think I get it! thanks.

OpenStudy (jdoe0001):

yw

OpenStudy (anonymous):

Wait what happens to the -3 coeffecient?

OpenStudy (anonymous):

Nvm, got the right answer

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