Question

thanks

Answer 1

..........................................


idk

Answer 2

In general, y = A*tan(Bx-C) + D

has a period of T = pi/B

Answer 3

hopefully you've encountered that form in your lessons

Answer 4

\(\bf \textit{function transformations}
\\ \quad \\

\begin{array}{llll}

\begin{array}{llll} shrink\ or\\ expand\\ by\ {\color{purple}{ A}}\cdot {\color{blue}{ B}}\end{array}
\qquad
\begin{array}{llll} vertical\\ shift\\ by \ {\color{green}{ D}} \end{array}

\begin{array}{llll}{\color{green}{ D}} > 0& Up\\ {\color{green}{ D}} < 0 & Down\end{array}
\\

\qquad \downarrow\qquad\qquad\quad\ \downarrow\\
y = {\color{purple}{ A}} ( {\color{blue}{ B}}x + {\color{red}{ C}} ) + {\color{green}{ D}}\\
\qquad\qquad\quad\ \uparrow \\

\qquad\begin{array}{llll} phase\\ shift\\ by \ \frac{{\color{red}{ C}}}{{\color{blue}{ B}}}\end{array}

\begin{array}{llll}\frac{{\color{red}{ C}}}{{\color{blue}{ B}}} > 0 & to \ left\\ \frac{{\color{red}{ C}}}{{\color{blue}{ B}}} < 0& to \ right\end{array}
\end{array}
\\ \quad \\ \quad \\



y={\color{purple}{ 3}}tan\left({\color{blue}{ 4}}x{\color{red}{ -\frac{\pi}{3}}}\right)\qquad period\implies \cfrac{\pi}{{\color{blue}{ B}}}\)

Answer 5

4

Answer 6

@jdoe0001

Answer 7

B = 4, but that's not the full answer (it's part of it)

Answer 8

then pi/12 ? @jim_thompson5910

Answer 9

what did you get for the period

Answer 10

@jim_thompson5910

Answer 11

i think it d

Answer 12

yeah, period = pi/4 and phase shift = pi/12

Answer 13

based on what jdoe0001 posted

Answer 14

thanks!!!!! so much

Answer 15

np