Question

Could someone please help me? It's Calculus

Answer 1

\[\sqrt{x+1}-1/x\]
x= -0.001, -0.01, -0.1, 0, 0.001, 0.01, 0.1

Answer 2

oh and lim x --> 0

Answer 3

Is this
\[
\frac{ \sqrt{x+1}-1 }x
\]
?

Answer 4

yes<3

Answer 5

Take \[
f(x)=\sqrt{x+1}
\]

Answer 6

The limit should be what in function of f(x)?

Answer 7

well i know you're suppose to plug and chug those numbers but i kept getting 1 except when i was at 0

Answer 8

\[
\lim_{x->0}\frac{f(x) -f(0) }{x-0}=f'(0)
\]

Answer 9

could you put that in table form?

Answer 10

\[f'(x)=\frac{1}{2 \sqrt{x+1}}
\\
f'(0)=\frac 12
\]

Answer 11

\[
\left(
\begin{array}{cc}
-0.001 & 0.500125 \\
-0.01 & 0.501256 \\
-0.1 & 0.513167 \\
0 & \text{Indeterminate} \\
0.001 & 0.499875 \\
0.01 & 0.498756 \\
\end{array}
\right)
\]
You can see that the limits is approaching .5

Answer 12

where did you get the 2

Answer 13

Are you still here?

Answer 14

no i got it, i had a brain fart, sorry for the stupid question lol