Question

3 log2 (x-1) + log2 4=5

Answer 1

HI!!

Answer 2

do you know that \(\log_2(4)=2\) since \(2^2=4\) ?

Answer 3

first work out \(\log_2 4\) :
\[\large 4 = 2^?\]

Answer 4

that means you have
\[3\log_2(x-1)+2=5\\
3\log(x-1)=3\] before you even start with those properties of the log

Answer 5

then divide both sides by 3, and finally write in equivalent exponential form

Answer 6

you got this from there ?

Answer 7

The answer is 3

Answer 8

In my book

Answer 9

idk lets see
\[3\log_2(x-1)=3\\
\log_2(x-1)=1\\
x-1=2^1\] yeah i guess \(x=3\)