Hi! Can anyone help me out with a small redox reaction?
\[S2H2+HN2O2 \rightarrow (S2O6)-2 +NH2OH\]
How can I calculate the oxidation number for N? H is +1, and O is -2 time 2 so it's -4, is it possible the Oxidation number for N will be 1.5?!
@iGreen
Maybe there's a mistake in the question?
Errr...I have no idea..
Thanks though!
@JFraser What do you think?
ill have to look at it for a minute
thank you!
if that formula is correct, the oxidation of the nitrogen in the reactant would have to be 1.5, which doesn't happen. I'd suggest that the formula in the reactant be \(HNO_2\), which is nitrous acid.
I knew it! Thanks allot! and one more clarification if I may ask, \[A: Ca^+2 +2e \rightarrow Ca (E= -2.87) or B: Rb^+2 +2e \rightarrow Rb (E= -2.925)\]
which one is a deuction cell and which one is the oxidizing cell?
reduction
i can't answer that with the information you've provided. Is there more?
no, that's all
they say that both of them are reduction reactions
but which of them is a reduction half cell and which one of them is an oxidizing half cell?
it doesn't make sense to answer on it without more details, is it?
*does it
@JFraser it's just gen chem but they endeavor to make hard life for us lol
both reactions are listed as reductions, that's true
but when they are \(combined\), one of them will be forced to "run" backwards and be an oxidation
right! but how can you tell which one of them? the answer is that A will be a reduction half cell and B will be an oxidation half cell
but how am I supposed to figure that out? by the E?
you look at the E values they give, which are the \(reduction\) potentials. The LARGER reduction potential will stay a reduction. The SMALLER reduction potential will be the reaction that flips backwards and will be the oxidation
so it's a negative E and hence A will go through reduction since it's bigger compared to B?
is that the reason?
@JFraser am I right?
A has a larger reduction potential than B, so when you pair them together, A will be the reduction and B will be flipped and be the oxidation. Yes
Thank you!!!! You are brilliant!!!!!
YW
I hope one day to help in return
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