use the trigonometric function vngles given in this section to evaluate each experssixpression such as cot"2 90° means (cot90°)"2 , which is equal to 0"2 = 0. sec"2 180° -35in"2 360° +cos180°
what? I don't understand... do you mean \[\sec^2(180^o)-3 \sin^2(360^o)+\cos(180^o)\]?
Yes :)
do you know how to evaluate cos(180)?
yes it is -1... according of what my teacher said..
\[\sec^2(180)-3 \sin^2(360)+\cos(180) \\ \frac{1}{(\cos(180))^2}-3(\sin(360))^2+\cos(180)\]
all you really need to do for this question is know how to evaluate cos(180) and sin(360) the rest his order of operations
but why do you convert sec to cos? and what do I do with the 2's?
sec(x)=1/cos(x)
cos and sec are reciprocal functions of one another
can you tell me what cos(180) and sin(360) equals?
cos= -1 and sin =0
so we are just going to replace those items real quick like this: \[\sec^2(180)-3 \sin^2(360)+\cos(180) \\ \frac{1}{(\cos(180))^2}-3(\sin(360))^2+\cos(180) \\ \frac{1}{(-1)^2}-3(0)^2+-1 \]
now just apply order of operations
all equal -3?
1-3(0)-1 isn't -3
0?
seems great me so if cos(180)=-1 then squaring both sides gives you (cos(180))^2=(-1)^2=1 and if sin(360)=0 then squaring both sides gives you (sin(360))^2=(0)^2=0 so yes we have 1-3(0)-1=1-0-1=1-1=0
Ya ! Thank you so much for heping me @freckles have a nice day ;)
Join our real-time social learning platform and learn together with your friends!