Question

MEDAL
I JUST NEED THE ANSWER
WILL POST QUESTION

Answer 1

division = multiplication by the reciprocal. start by flipping the right hand side

next, factor the stuff in parentheses

Answer 2

so i flip the right side and it becomes multiplication then what?

Answer 3

factor both numerators and denominators

Answer 4

I didn't mean to distribute it just yet

Answer 5

dang it

Answer 6

yeah i don't know how to factor it

Answer 7

btw the stuff in parentheses are m's not n's :p

Answer 8

\(\large \frac{5n^2\color{red}{(m^2+2m-3)}}{10n(m^2-3m+2))}\times\frac{4n^2(m^2-8m+12)}{n^2(m^2-3m-18)}\)

start with the red

Answer 9

m?

Answer 10

I don't understand this problem at all this is the first time I've come across a problem like this

Answer 11

that's weird. so you can't factor \((m^2+2m-3)\)?
rewrite it as (m+?)(m-?)

Answer 12

find two number if you multiply them you should get -3 and if you add or subtract them you should get positive 2

Answer 13

(m+3)(m-1)

Answer 14

that's right :)

Answer 15

ok thank you that helps, so after i factor it THEN i distribute?

Answer 16

if you distribute u gonna get same thing

Answer 17

nope. then you cancel what you can

Answer 18

distributing would make things very ugly. if you notice, they're not even the same letters

Answer 19

ohhh i see

Answer 20

yeah^

Answer 21

ok hold on I will try factoring it

Answer 22

\[\frac{ 5n^2(m+3)(m-2) }{ 10n(m-1)(m-2) } \times \frac{ 4n^2(m-2)(m-6) }{ n^2(m+3)(m-6) }\]

Answer 23

i could cancel out the (m-2) and the (m-6) right?

Answer 24

wait nope i copied it down wrong

Answer 25

should be (m-1)

Answer 26

yes left side top part its ( m -1) not (m -2)

Answer 27

yeah i know i just typed it out wrong i have it the right way on my paper

Answer 28

also the m+3s

Answer 29

\(\large \frac{ 5n^2\cancel{(m+3)}\cancel{(m-1)} }{ 10n\cancel{(m-1)}(m-2) } \times \frac{ 4n^2(m-2)\cancel{(m-6)} }{ n^2\cancel{(m+3)}\cancel{(m-6)} }\)

Answer 30

hmmmmmmmm

Answer 31

wait is the top right, correctly factored

Answer 32

it should be..

Answer 33

yes right -6 times -2 = 12
and -2 =-8
yeah looks good

Answer 34

oh, I was looking at the original division thing

Answer 35

forgot we flipped it

Answer 36

so am I left with ? \[\frac{ 5n^2 }{ 10n } \times \frac{ 4n^2 }{ n^2 }\]

Answer 37

yeah. you can cancel an n^2 and simplify 5/10

Answer 38

whoops

Answer 39

\[\frac{ 2n^2 }{ 5n } \times 4\]

Answer 40

5/10=1/2

Answer 41

oh yeah whoops haha thats basic math

Answer 42

i am ashamed

Answer 43

so is 2n my answer?

Answer 44

yeah