@bibby can u Plzzzz help mee?!?
HI!!
help with what?
i bet it is trig
Graph the six terms of a finite series where a1 = -3 and r = 1.5. graphed sequence showing point 1, 2.25, point 2, 3.75, point 3, 8.25, point 4, 21.75, point 5, 62.25, and point 6, 183.75 graphed sequence showing point 1, 1.5, point 2, 3.75, point 3, 10.5, point 4, 30.75, point 5, 91.5, and point 6, 273.75 graphed sequence showing point 1, negative 9, point 2, negative 12, point 3, negative 16.5, point 4, negative 23.25, point 5, negative 33.38, and point 6, negative 48.56 graphed sequence showing point 1, negative 3, point 2, negative 7.5, point 3, negative 14.25, point 4, negative 24.38, point 5, negative 39.56, and point 6, negative 62.34
\[a_1=-3,a_2=-3\times 1.5=-4.5, a_3=-3(1.5)^2=-6.7\]
does on start out \((1,-3),(2,-4.5),(3,-6.75)\)
i don't see it i has to start out \((1,-3)\)
it's D!! thxx! @satellite73
yeah but the second one should be \((2,-4.5)\) and it is not ...
unless it really should be a1 = -3, r=2.5
no r is 1.5
I dont see the answer either
@satellite73
hmm then there is a mistake has to be -3,-4.5,-6.75, ... not sure what advice to give, i am certain that is the answer
ughhh
really nothing you can do i assume these are pictures right?
yes
i'll attach them
it really has to start \((1,-3)\)since it tell you \(a_1=-3\) unless that is typo
yeah and D starts with (1, -3)
@satellite73
ok fine the correct answer is not there, go with D and move on not worth fretting about you are sure a1 = -3, r = 1.5 right? don't sweat it, don't get frustrated, moveon.org or write and say the correct answer is not shown
i cant write its multiple choice and yes i'm sure
Calculate the average rate of change for the graphed sequence from n = 2 to n = 4. graphed sequence showing point 1, negative 3, point 2, negative 3.5, point 3, negative 6.75, point 4, negative 10.125, point 5, negative 15.1875, and point 6, negative 22.78125 -6.625 -03.3125 -3.0 -2.0
then you have to accept defeat they made a mistake, there is nothing you can do don't worry about it if there is really no way to write them, (which is stupid) then you can do nothing
\[\frac{-10.125+5.3}{4-2}\]
oops
i got -3.21
yeah B
Graph the first six terms of a sequence where a1 = -10 and d = 3. graphed sequence showing point 1, negative 10, point 2, negative 7, point 3, negative 4, point 4, negative 1, point 5, 2, and point 6, 5 graphed sequence showing point 1, negative 7, point 2, negative 4, point 3, negative 1, point 4, 2, point 5, 5, and point 6, 8 graphed sequence showing point 1, negative 7, point 2, negative 17, point 3, negative 27, point 4, negative 37, point 5, negative 47, and point 6, negative 57 graphed sequence showing point 1, 3, point 2, negative 7, point 3, negative 17, point 4, negative 27, point 5, negative 37, and point 6, negative 47
ok we really gotta stop that "point" stuff just type it in or copy or something this si like impossible to read
okay sorry
lets just compute it
\[-10,-10+3,-10+2*3,-10+3*3...\] or \[-10,-7,-4,-1,2,...\]
A (1,-10) (2,-7) (3,-4) (4,-1) (5,2) (6,5)
that looks good go no further
so thats the answer?
yes
thanks!!
Calculate the average rate of change for the graphed sequence from n = 2 to n = 6. graphed sequence showing point 1, 17, point 2, 14, point 3, 11, point 4, 8, point 5, 5, and point 6, 2 -9 -4 -3 -2
@satellite73
\[\frac{2-14}{6-2}\]
thanks!! last one!
i.e \(-3\)
Graph the first six terms of a sequence where a1 = 2 and r = 4. graphed sequence showing point 1, 8, point 2, 16, point 3, 32, point 4, 64, point 5, 128, and point 6, 256 graphed sequence showing point 1, 8, point 2, 8, point 3, 16, point 4, 32, point 5, 64, and point 6, 128 graphed sequence showing point 1, 2, point 2, 8, point 3, 32, point 4, 128, point 5, 512, and point 6, 2048 graphed sequence showing point 1, 8, point 2, 32, point 3, 128, point 4, 512, and point 5, 2048, point 6, 8192
wait -3 or -4 i got -4
@satellite73
\[2-14=-12\\ 6-2=4\] and \(-12\div 4=-3\) right?
oops lol
ok for the last one, \(a_1=,,r=4\) right ?
oops \(a_1=2,r=4\)
a1 is 2
ok so \[(1,2),(2,8),(3,32),(4,128)\] etc
(5,512) (6,2048) yes
yeah you are multiplying by 4 each time
yeah thanks
that it?
yep!! got a 100%
lol imagine
xD
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