Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (wade123):

someone explain this?!

OpenStudy (anonymous):

i really doubt it since there is no h in the question

OpenStudy (wade123):

@satellite73 @srossd sorry i meant 5, i was supposed to skip 4

OpenStudy (loser66):

from [0,6], f(x) = -x+3, hence f(t) =-t+3 then \[g(x) =\int_{-2}^x f(t)dt = \int_{-2}^x (-t+3) dt =??\]

OpenStudy (anonymous):

easiest to draw a picture of your piecewise function and use geometry

OpenStudy (anonymous):

from \(-2\) to \(0\), \(g(x)=3x\)

OpenStudy (anonymous):

|dw:1422115766179:dw|

OpenStudy (anonymous):

you want the function that gives you the area under that curve

OpenStudy (wade123):

@SithsAndGiggles

OpenStudy (wade123):

@SithsAndGiggles what do i do next? im confusedd

OpenStudy (anonymous):

Everything you need has been provided in @Loser66's comment.

OpenStudy (wade123):

so when i solve that, im done?

OpenStudy (wade123):

i didnt even see that comment, just satelites

OpenStudy (wade123):

so it would be x^2/2-3x-8??? @SithsAndGiggles

OpenStudy (anonymous):

Check your negative signs. Your answer isn't far off. You integrated over the interval \([x,-2]\); you're supposed to use \([-2,x]\).

OpenStudy (anonymous):

Yeah, that's right. Though I recommend not completely relying on W|A to compute everything for you.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!