someone explain this?!
i really doubt it since there is no h in the question
@satellite73 @srossd sorry i meant 5, i was supposed to skip 4
from [0,6], f(x) = -x+3, hence f(t) =-t+3 then \[g(x) =\int_{-2}^x f(t)dt = \int_{-2}^x (-t+3) dt =??\]
easiest to draw a picture of your piecewise function and use geometry
from \(-2\) to \(0\), \(g(x)=3x\)
|dw:1422115766179:dw|
you want the function that gives you the area under that curve
@SithsAndGiggles
@SithsAndGiggles what do i do next? im confusedd
Everything you need has been provided in @Loser66's comment.
so when i solve that, im done?
i didnt even see that comment, just satelites
so it would be x^2/2-3x-8??? @SithsAndGiggles
Check your negative signs. Your answer isn't far off. You integrated over the interval \([x,-2]\); you're supposed to use \([-2,x]\).
Yeah, that's right. Though I recommend not completely relying on W|A to compute everything for you.
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