Question

Algebra 1 question :D
Medal + Fan!

Answer 1

A quadratic equation is shown below:

9x^2 - 36x + 36 = 0

Describe the solution(s) to the equation by just determining the radicand. Show your work.

Answer 2

divide by 9 first

Answer 3

ok gimme a sec :D

Answer 4

x^2−4x+4

Answer 5

(refresh page)

Answer 6

would that be correct @satellite73 ?

Answer 7

lol

Answer 8

\[x^2-4x+4=0\] is the start

Answer 9

then it is a perfect square, namely \((x-2)^2=0\)

Answer 10

ok then what should I do next...

Answer 11

say if \(x-2=0\) then \(x=2\) and be done with it

Answer 12

ok then, and was that the solution by just determining the radicand? @satellite73

Answer 13

also @satellite73 , why did you go from (x−2)^2=0 to x−2=0?

Answer 14

because if the square of a number is zero, the number itself must be zero

Answer 15

ah ok, so overall, you determined the solution by just determining the radicand? @satellite73

Answer 16

i am not sure of this terminology
to me the radicand means the number inside the radical

Answer 17

so i you had \((x-2)^2=0\) i guess you could say \(x-2=\sqrt 0\) and the radicand would be 0

Answer 18

same here, but if that meant determining the number inside the radical, would the answer than be x−2=0√ and the radicand would be 0?

Answer 19

yes i guess, but that makes \(x-2=0\) you want \(x\) which is \(2\)

Answer 20

ok, mind helping me with one more?

Answer 21

thanks btw :D

Answer 22

sure no problem

Answer 23

A sandbag was thrown downward from a building. The function f(t) = -16t^2 - 32t + 128 shows the height f(t), in feet, of the sandbag after t seconds.

Question: Factor the function f(t) and use the factors to interpret the meaning of the x-intercept of the function.

Answer 24

we can factor this for sure

Answer 25

ok then...

Answer 26

first take out the common factor of \(16\)

Answer 27

or better yet, \\(-16\)

Answer 28

yeah yeah... gimme a sec

Answer 29

wait but how?

Answer 30

how to factor out the \(-16\)?

Answer 31

yeah

Answer 32

\[-16t^2-32t+128=-16(something)\]

Answer 33

it it clear what you get or no? if not i will show you

Answer 34

no no, I can do this :D

Answer 35

ok then it will be easy to factor

Answer 36

whoa hold the phone tooooo much work
it says factor, not solve the quadratic

Answer 37

ok sorry about that

Answer 38

\[-16t^2-32t+128=-16(t^2+2t-8)\]is a start

Answer 39

−16t^2−30t+136=−16(t^2)

Answer 40

−15t^2−30t+136=−16

Answer 41

oh my

Answer 42

what... did I go deep down wrong?

Answer 43

i will try to say it again

\[-16t^2-32t+128\] each term has a common factor
that common factor is \(16\) or \(-16\)

Answer 44

OH YES THEY DO I JUST NOTICED :D

Answer 45

so job number one is to "factor it out" i..e factor out the \(-16\) from each term

Answer 46

(t^2)-2t+8

Answer 47

no wait, sorry (t^2)-2t-8

Answer 48

actually
\[-16(t^2+2t-8)\]

Answer 49

oh right... what next?

Answer 50

then leave the \(-16\) hanging out front, and see if you can factor
\[t^2+2t-8\] which should not be too hard

Answer 51

(x−2)(x+4)

Answer 52

damn question marks
should be \((t-2)(t+4)\) if that is what you have then yes

Answer 53

ikr.... oh sorry, I accidentally replaced t with x :P

Answer 54

makes no real difference

Answer 55

ok then, so, did we just interpret the meaning of x-intercept in this equation?

Answer 56

it is is when the height is zero
there are two intercepts \((t=2,t=-4\) but since we don't really go back in time, \(t=-4\) is not meaningful in this question, and what this means is it took two seconds to hit the ground

Answer 57

ok then, thank you, and have a good rest of your day :D

Answer 58

you too, and congratulations on getting in to oxbridge !

Answer 59

how did you know?

Answer 60

psychic

Answer 61

haha... well thanks again, bye :D

(it was facebook wasn't it?)

Answer 62

yes, it was

Answer 63

and your welcome any time

Answer 64

:D