Question

Solve by graphing

Answer 1

first you have to solve for y

Answer 2

can you solve both equatiosn for y ?

Answer 3

I got the points for the first as (0,4), (2,5), (4,6)?

Answer 4

and for the second I got (0,0), (0,1), (0,2)

Answer 5

oops I mean (0,0), (2,1), (4,2) for the 2nd

Answer 6

points??
to check it you can replace x and y by their values and see if you get both side equal

Answer 7

That's what I got my graph to look like

Answer 8

I don't know this is how someone told me to do it but I'm lost

Answer 9

hint: \(\bf \text{"Solve by graphing"}\)

Answer 10

nope that's wrong

Answer 11

I have no clue then

Answer 12

in order to be parallel lines
both equations should have same slope

Answer 13

Then I'm lost on where to start

Answer 14

are you sure u plugged that right into calculator ??

Answer 15

hmmm do you know how to simplify linear equations?
that is, what Nnesha said, solvinng for "y"

Answer 16

I did it myself, I don't know how to plug in a graph

Answer 17

That's what I thought I was doing

Answer 18

so what did you get after solving each for "y" then?

Answer 19

Those are the points I got, but I guess I didn't do it right

Answer 20

yeah that is not right bec if you use one of order pair and plugg that into equations u are not gonna get equal side and that's mean
that order pair is not solution

Answer 21

@jdoe0001 <-- he can hep ou
i gtg now
sorry its urgent ^_^

Answer 22

Ok thanks

Answer 23

For the first I got y=1/2x-4

Answer 24

you need help

Answer 25

hello

Answer 26

Yes please

Answer 27

ok

Answer 28

i have a guy that can help see math is not my subject let me give the guy a call

Answer 29

yeap, the 1st one is correct
to graph that just pick 2 points
say x = 0
and use the y-intercept, or when y=0
notice that the slope-intercept form gives away the y-intercept
\(\bf y=\cfrac{1}{2}x{\color{blue}{ -4}}\qquad {\color{blue}{ y-intercept}}\)

Answer 30

and use the y-intercept, or when x=0 rather

so... hmm

Answer 31

@vshiroky your welcome

Answer 32

So I put 0 where x is?

Answer 33

um let me call the guy again

Answer 34

@jdoe0001 for the 2nd equation I got y=1/2x

Answer 35

he is coming

Answer 36

well
let us get two points, and thus 2 values for "x"
let use pick say x = 0, that gives the y-intercept anyhow, which is -4
thus ( 0, -4 )

so another point , say let us make y = 0 for simplicity
one sec

Answer 37

k

Answer 38

I still don't understand what you mean

Answer 39

so.. here are your two equations, and a couple of points to plot them \(\bf y=\cfrac{1}{2}x-4
\begin{cases}
x=0\qquad y=-4&(0,-4)\\
\hline\\
y=0\\
0=\frac{1}{2}x-4\to 4=\frac{x}{2}\to 8=x&(8,0)\\
\end{cases}
\\ \quad \\
y=\cfrac{1}{2}x
\begin{cases}
x=0\qquad y=0&(0,0)\\
\hline\\
y=0\\
0=\frac{1}{2}x\to 0=x&(0,0)
\end{cases}\)

Answer 40

notice something
their slope of 1/2, is the same in each
same slope = parallel lines

Answer 41

parallel lines never touch each other, thus, a solution is when the graphs intersect
no intersect, no solution

Answer 42

hmmm

Answer 43

hold the mayo for a sec, the 2nd equation.... is a bit off
lemme do that one quick

Answer 44

x+2y = 0
2y = -x
y = -x/2 <-- minus

Answer 45

\(\bf y=\cfrac{1}{2}x-4
\begin{cases}
x=0\qquad y=-4&(0,-4)\\
\hline\\
y=0\\
0=\frac{1}{2}x-4\to 4=\frac{x}{2}\to 8=x&(8,0)\\
\end{cases}
\\ \quad \\
y=-\cfrac{1}{2}x
\begin{cases}
x=0\qquad y=0&(0,0)\\
\hline\\
y=0\\
0=\frac{1}{2}x\to 0=x&(0,0)
\end{cases}\)

the slopes differ, one is negative, the other positive, thus they should intersect, and thus have a solution

Answer 46

anyhow, for the one is... \(\large {
y=-\cfrac{1}{2}x
\begin{cases}
x=0\qquad y=0&(0,0)\\
\hline\\
y=0\\
0=-\frac{1}{2}x\to 0=x&(0,0)
\end{cases}}\)

Answer 47

I have no clue what just happened

Answer 48

This is making 0 sense to me

Answer 49

hmm what part?

Answer 50

site is a bit laggy, so you know

Answer 51

Any of it

Answer 52

How do I graph 0,0

Answer 53

ok... well...can you follow where we got the coordinates for each from their equation?
\(y=\cfrac{1}{2}x-4
\begin{cases}
x=0\qquad y=-4&(0,-4)\\
\hline\\
y=0\\
0=\frac{1}{2}x-4\to 4=\frac{x}{2}\to 8=x&(8,0)\\
\end{cases}
\\ \quad \\
y=-\cfrac{1}{2}x
\begin{cases}
x=0\qquad y=0&(0,0)\\
\hline\\
y=0\\
0=-\frac{1}{2}x\to 0=x&(0,0)
\end{cases}\)

Answer 54

No and I'm on my last attempt so I'm gunna get it wrong and have to do a whole new problem

Answer 55

ok.... can you see how we get 0,-4 from the 1st equation then?

Answer 56

no

Answer 57

ok
\(\bf y=\cfrac{1}{2}x-4\qquad x={\color{brown}{ 0}}\implies y=\cfrac{1}{2}{\color{brown}{ 0}}-4\implies y=0-4\implies y=-4
\\ \quad \\
x=0\qquad y=-4\implies (0,-4)\)

see it now?

Answer 58

yea

Answer 59

what about the other values.... they were obtained by doing the same thing
setting "x" or "y" to some value, in this case 0, and getting the value of the other

folllow that?

Answer 60

is this right?

Answer 61

http://fooplot.com/#W3sidHlwZSI6MCwiZXEiOiIxLzJ4LTQiLCJjb2xvciI6IiNENDJBMkEifSx7InR5cGUiOjAsImVxIjoiLTEvMngiLCJjb2xvciI6IiMzNTNBQ0MifSx7InR5cGUiOjEwMDB9XQ-- I'd say yes

Answer 62

thank you. I'm not gunna do the others I don't think I can

Answer 63

yw

Answer 64

why not
\(\huge\color{green}{{\rm you }~\rm can !! :)}\) \(\Huge \color{gold}{\star^{ \star^{\star:)}}}\Huge \color{green}{\star^{ \star^{\star:)}}}\)

try :)

Answer 65

@jdoe0001 thanks :)