Question

What is the restriction on the product?

Answer 1

\[\frac{ x^2+3x+2 }{ x^2-2x-3 } * \frac{ x^2+4x+3 }{ x+2 }\]

Answer 2

@perl

Answer 3

the restrictions are x such that the denominator becomes zero

Answer 4

So x ≠ -2 would be the answer?

Answer 5

you cant have x values which cause the denominator to equal to zero (since division by zero is undefined)

Answer 6

i would start by factoring the denominator

Answer 7

yes that is one restriction, x cannot equal to -2

Answer 8

@iambatman Is x ≠ -2 the only answer to this question?

Answer 9

Idk what did you get when you simplified it?

Answer 10

I haven't simplified it yet....

Answer 11

But yes, x = -2 I see

Answer 12

cannot

Answer 13

Hold on while I simplify it...

Answer 14

Ah I see what it cannot be :), lets see if you can figure it out!

Answer 15

I got (x+1)(x+3)/(x-3)

Answer 16

\[\frac{ stuff }{ (x+1)(x-3)(x+2) }\]

Answer 17

These are my answer choices:

A. x ≠ -3
B. x ≠ 3
C. x ≠ 1
D. x ≠ -2

I think the answer is D...

Answer 18

Am I right? @iambatman

Answer 19

Can you pick more than 1?

Answer 20

No I can only choose one.

Answer 21

That's weird. Yes x cannot = -2.

Answer 22

Ok so the answer is D?

Answer 23

Ah I see, x cannot = - 1 is the other :)

Answer 24

Yes, D is good!

Answer 25

Thank you :)