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Mathematics 11 Online
OpenStudy (anonymous):

Find the indicated limit, if it exists.

OpenStudy (anonymous):

OpenStudy (xapproachesinfinity):

you need to find the limit from the left of -1 and from the right of -1 first

OpenStudy (anonymous):

can you help me? I don't get this lesson, i don't know how to do that.

OpenStudy (xapproachesinfinity):

for the limit from the left you need to consider f(x)=4-x if x<-1 \[\large \lim_{x\to-1^{-}}4-x=4-(-1)=5\] for the limit from the right you consider f(x)=x+6 if x>-1 \[\large \lim_{x\to-1^+}x+6=-1+6=5\] since \[\large \lim_{x\to-1^-}f(x)=\lim_{x\to-1^+}f(x)=5\] then we say the \[\large \lim_{x\to -1}f(x)=5=f(-1)\] so the limit exist

OpenStudy (xapproachesinfinity):

if the two limit don't equal each other then the limit would exist

OpenStudy (xapproachesinfinity):

wouldn't*

OpenStudy (anonymous):

so they have to equal eachother? and do you not do anything with the middle piece? the 5 x=-1 or is that what the other two should equal?

OpenStudy (xapproachesinfinity):

yes! the middle part no nothing in particular it just told us here that f(-1)=the limit =5 sometimes this does not happen

OpenStudy (anonymous):

thank you so much! I think I get it, but can I have you check 2 other problems for me to make sure i did it right?

OpenStudy (xapproachesinfinity):

welcome! i have to go sorry

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