Mathematics
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OpenStudy (pratyush5):
Question on binomial theorem
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OpenStudy (pratyush5):
\[\sum_{r=0}^{n}r ^{2} C _{r}^{2}\]
OpenStudy (pratyush5):
@UnkleRhaukus
OpenStudy (misty1212):
HI!!
OpenStudy (misty1212):
how are you interpreting \(\binom{2}{r}\) for \(r>2\)? usually that is zero
OpenStudy (misty1212):
in which case this is only
\[1^2+2^2=5\]
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OpenStudy (pratyush5):
I don't get you. Plus that 2 on the top means square, if that's what you are asking.
OpenStudy (misty1212):
oh ok then what does \(C_2\) mean?
OpenStudy (misty1212):
sorry i meant \(C_r\)
what is being squared?
OpenStudy (pratyush5):
\[C _{r}\] is being squared
OpenStudy (misty1212):
ok let me ask it this way
what is \(C_3\) ?
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OpenStudy (xapproachesinfinity):
that's clearly 2 choose r
\[C_{r}^{2}\]
OpenStudy (misty1212):
@xapproachesinfinity apparently it is not (according to @pratyush5 )
OpenStudy (pratyush5):
Wait, I am gonna write the question another way.
OpenStudy (xapproachesinfinity):
that's not squared?
OpenStudy (xapproachesinfinity):
are you sure!?
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OpenStudy (misty1212):
\(C_r\) is not defined yet, if it is some quantity to be squared
if it is \(C_r^2=\binom{2}{r}\) then it is zero if \(r>2\)
OpenStudy (pratyush5):
\[1^{2.}C _{1}^{2} + 2^{2}.C _{2}^{2} + 3^{2}.C _{3}^{2} ......\] and so on
OpenStudy (pratyush5):
|dw:1422196740633:dw|
OpenStudy (xapproachesinfinity):
if so you will have something of this form C1 C2 C3 C4 with the square remaining on top
OpenStudy (pratyush5):
@xapproachesinfinity Thats what I have.
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OpenStudy (misty1212):
ok then it is 5
OpenStudy (xapproachesinfinity):
|dw:1422196801890:dw|