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Mathematics 19 Online
OpenStudy (anonymous):

find the perimeter and area of the following composite shape. {show work}

OpenStudy (anonymous):

OpenStudy (displayerror):

The perimeter is the distance around the object. Think about taking a string and walking along the outside of a square or circle--that is the perimeter (or circumference in the case of a circle). To find the perimeter of the object, add the circumference of the semicircle with the perimeter of the rectangle. \[\text{Circumference} = \pi \times D\] \[\text{Perimeter} = 2L + 2W\] The area is the space occupied by the 2D object. Think about shading the inside of a circle or the inside of a rectangle--that is the area. To find the area of the object, add the area of the semicircle with the area of the rectangle. \[\text{Area}_{circle} = \pi \times \text{Radius}^2\] \[\text{Area}_{rect} = L \times W\]

OpenStudy (anonymous):

i did it already. i know the answer to it but i have to show the work. & i dont know how to do it.

OpenStudy (anonymous):

what shape is this

OpenStudy (anonymous):

a rectangle and a semi circle

OpenStudy (anonymous):

a mixture?

OpenStudy (anonymous):

what grade

OpenStudy (displayerror):

You've done the problem already but you don't know how to do it? The "work" that you have to show would be applying those equations above. You would specify what the length and width of the rectangle is and what the diameter of the circle is (which leads you to the radius).

OpenStudy (anonymous):

@partyrainbow276 what grade

OpenStudy (anonymous):

9th

OpenStudy (anonymous):

sorry im in 7th

OpenStudy (anonymous):

well this is very confusing.

OpenStudy (displayerror):

What is it that you don't get? Do you know how to find the area and circumference of the semicircle? What about for the rectangle?

OpenStudy (anonymous):

yeah i do but i keep getting the wrong answer when i show the work.

OpenStudy (displayerror):

From the figure, what is the diameter of the circle? Notice that the diameter of the circle is one part of the rectangle.

OpenStudy (anonymous):

20.2

OpenStudy (displayerror):

Right, so we have that \(\text{Diameter} = 20.2 \ \text{mm}\). What is the radius? Remember that \(\text{Radius} = \text{Diameter} \times \frac{1}{2}\) The area of a semi (half) circle is given by \[\text{Area} = \frac{1}{2} \times \pi \times \text{Radius}^2\] What is the area of the semicricle in the figure?

OpenStudy (anonymous):

160.1557

OpenStudy (displayerror):

Right. Now what is the area of the rectangle? The area of a rectangle is given by \[\text{Area} = \text{Length} \times \text{Width}\] Don't worry about which side is the length and which side is the width--just know that they are two different sides of a rectangle.

OpenStudy (anonymous):

62.62

OpenStudy (displayerror):

Right. Now add the area of the circle and the area of the rectangle (which you have provided the answers to) and that is the area of your shape.

OpenStudy (nirmalnema):

area of the given fig. = area of rectangle + area of semicircle. =(3.1*20.2) + (1/2 * 3.14*10.1*10.1) = 62.62+ 160.1557 =222.7757

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