Determine if the graph is symmetric about the x-axis, the y-axis, or the origin. r = -2 + 3 cos θ
is there an answer choice
@faariat
what do you mean its either symmetric one of those ways
there are rules for symmetry
If replacing (r, theta) by (r, -theta) gives an equivalent equation, the graph is symmetric with respect to the polar axis (the horizontal axis)
replace theta with -theta in the equation -2 + cos(-theta) = =2 + cos(theta) = r therefore it is symmetric with respect to polar axis
Symmetry is a helpful tool when graphing in Polar Coordinates. If replacing (r; ) by (r;) gives an equivalent equation, the graph is symmetric with respect to the polar axis (the horizontal axis). For example, if r = cos and we replace by , we get r = cos() = cos since cosine is an even function. Since this is what we started with, we know that the graph is symmetric with respect to the polar axis. If replacing (r; ) by (r; ) or (r;) gives an equivalent equation, the graph is symmetric with respect to the line = =2 (the vertical axis). For example, if r = sin , replacing r by r and by gives r = sin() = sin . After we cancel out the negative signs, this is exactly what we started with, so we know that the graph of r = sin is symmetric with respect to the line = =2. If replacing (r; ) by (r; + ) or (r; ) gives an equivalent equation, the graph is symmetric with respect to the pole (origin). For example, r = 5 and = =4 satisfy this criterion.
not sure what happened there
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