x+6/x^2+5x-6
What are the instructions for this?
i think we simplify
It's simplifying rational expressions but, it's where i'm weak atm
ok lts do this
is this alg1 or and does it have an answer choice
it's algebra 2 and nopes
ok so we first factor by grouping
rewrite 5x as -1(x)+6(x) x2-1(x)+6(x)-6 then after that group the first two terms and the last two terms (x2-1(x))+6(x)-6 then we factor x out of x2 xx-1(x)+6(x)-6 then after that we factor x out of -1(x) xx+x-1+6(x)-6
factor x out of xx + x-1 x(x-1)+6(x)-6 then we factor 6 out of 6(x)-6 x(x-1)+6(x-1) then we factor x-1 out of x(x-1)+6(x-1) (x+6)(x-1)
then replace back in to large expression x+6/(x+6)(x-1) then finally reduce the expression by cancelling the common factores cancel x+6 in the numerator and denominator (x+6)/(x+6)(x-1) which leaves (x-1) then we cancel x+6 in the num and den then your answer will be 1/x-1
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