Question

Calc question: A honeybee population grows at an annual rate equal to 1/4 of the number present when there are no more than 10,000 bees. If there are 1,000 bees now, when will the population reach 10,000?

Answer 1

Any help is appreciated

Answer 2

let N be the number of bees in the population in a particular year

Answer 3

dN/dt=1/4 * N

Answer 4

Yes

Answer 5

seperation of variables gives you the answer

Answer 6

so dN/N=0.25dt

Answer 7

The solution I have says dP/P=0.25t. Where did the d go?

Answer 8

maybe just a typo

Answer 9

No, it says online too

Answer 10

https://answers.yahoo.com/question/index?qid=20090413121458AARZKFg

Answer 11

You want to use the formula
\[N=N _{0}e ^{kt}\] Where N is the number of bees at time (year) t, N sub 0 is the number you start with, and k is the growth constant.

\[1.25=1.00e ^{1k}\] Solve for k

Answer 12

Where did you get any of those numbers

Answer 13

The 1.00 is arbitrary. That would be the number of bees you start with. After 1 year *(the 1 is the coefficient of k in the exponent) we have 1.25 bees. Start with 1000, we have 1250 next year - it's the same ratio.

Answer 14

Let me know when you've calculated k

Answer 15

That's not what my teacher said in this solutions thing

Answer 16

She has P(t)=5000e^0.25t

Answer 17

Plugged in 10,000 for P(t)

Answer 18

Well, is the solution 10.32 years?

Answer 19

No

Answer 20

2.77

Answer 21

It was similar to this https://answers.yahoo.com/question/index?qid=20090413121458AARZKFg

Answer 22

@SolomonZelman Please help me. I have been at this for over an hour and a half

Answer 23

Does that make any sense? If I start out with 1000 bees, I have 1250 after the first year.But wait, you just said you started with 1000 bees in the initial post. Looking at the question on answers, you started with 5000.

Answer 24

It's a similar question, but not the exact same one.

Answer 25

Start w/ 1000 bees
Carrying capacity= 10,000 bees
Grows at an annual rate = 1/4 present population

Answer 26

The formula I gave you is the standard exponential growth/decay formula. It's all you need, and the answer is 3.1 years. Makes a big difference if you start with 5000 bees instead of 1000.

Answer 27

I don't start with 1000 bees. I was using that as a model for how on Earth to do the problem. And my teacher's answer says 2.77, and I don't understand how she did it

Answer 28

"Calc question: A honeybee population grows at an annual rate equal to 1/4 of the number present when there are no more than 10,000 bees. If there are 1,000 bees now, when will the population reach 10,000?"

or

"Goneybee Population : A population of honey bees grows at an annual rate equal to 1/4 of the number present when there are no more than 10,000 bees. If there are more than 10,000 bees but fewer than 50,000 bees, the growth rate if equal to 1/12 of the number present. If there are 5000 bees now, when will ther ebe 25,000 bees?"

Answer 29

The first one

Answer 30

The second one is just cruel