Question

(3,-2) find sin θ

Answer 1

(3,-2) find sin

Answer 2

there's a theta at the end

Answer 3

hint: \(\bf tan(\theta)=\cfrac{opposite}{adjacent}=\cfrac{y}{x}\implies \theta=tan^{-1}\left(\cfrac{y}{x}\right)
\\ \quad \\

\begin{array}{cccllll}
(3&,&-2)\\
x&&y
\end{array}\)

Answer 4

hmm ohh ahemm shoot the sine =) ok

Answer 5

well, that'd be one way, you get the angle
then just take the sine of the angle found

Answer 6

recall your SOH CAH TOA

Answer 7

how would you graph it

Answer 8

just plot the point

Answer 9

wow... the hypotenuse is

\[h^2 = 3^2 + (-2)^2\]

Answer 10

you need to check your calculation carefully

Answer 11

hmmm \(\bf c^2=x^2+y^2\implies c=\sqrt{x^2+y^2}\implies c=\sqrt{(-2)^2+(3)^2}
\\ \quad \\
c=\sqrt{\square ?}\)

Answer 12

anyhow, and bear in mind that \(\bf {\color{brown}{ sin}}(\theta)=\cfrac{opposite}{hypotenuse}=\cfrac{y}{r}\)

Answer 13

5?