The area of a triangular sheet of paper is 69 square inches. One side of the triangle is 5 inches more than three times the length of the altitude to that side. Find the length of that side and the altitude to the side.
woops give me a sec i made a mistake
let the altitude be x and the height be 3x+5 69=(3x+5)(x)(1/2) 138=3x^2+5x 3x^2+5x-138=0 solve that trinomial
do you know how to use the quadratic formula? @Ehoyle26
gonna need a response for further help :)
no, I'm barely getting back into math again after almost 10 years
quadratic formula= \[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a}\]
a=3 b=5 c=-138 in your case
\[\frac{ -5\pm \sqrt{25+1656} }{ 6 }\]
solve that
So x= -23/3 and x=6
you will discard the negative part as it's not possible to have a negative length of a triangle
x=6 let the altitude be x and the height be 3x+5 plug x=6 back into to get altitude and height
so, the altitude is 6 and the height is 23?
Yes
Thank you so much! I appreciate your help!
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