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Mathematics 15 Online
OpenStudy (anonymous):

How to integrate the function?

OpenStudy (anonymous):

|dw:1422244301924:dw|

OpenStudy (mimi_x3):

partial fracs

OpenStudy (dumbcow):

yeah ^

OpenStudy (mimi_x3):

\[\int\frac{1}{x} - \frac{x}{x^2+1}dx\]

OpenStudy (mimi_x3):

the first integral is a logarithmic, the second is a simple u-sub

OpenStudy (kainui):

Alternative: \[\Large x= \tan \theta \\ \Large dx = \sec^2 \theta d \theta \]\[\Large \int\limits \frac{\sec^2 \theta d \theta}{\tan \theta(\tan^2 \theta + 1)} = \Large \int\limits \frac{\sec^2 \theta d \theta}{\tan \theta \sec^2 \theta} = \int\limits \frac{\cos \theta}{ \sin \theta} d \theta\] Which is \[\Large \ln|\sin \theta| +C= \ln | \frac{x}{ \sqrt{x^2+1}}|+C\]

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