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Mathematics 19 Online
OpenStudy (anonymous):

find measurement indicated.

OpenStudy (anonymous):

OpenStudy (eyust707):

When given a non-right triangle, two sides and one angle the easiest approach to use to find a missing side is the law of cosines

OpenStudy (anonymous):

but i only have one angle if i had two it would be easier.

OpenStudy (eyust707):

|dw:1422266958866:dw|

OpenStudy (eyust707):

In this case we want "b" right?

OpenStudy (eyust707):

well the law of cosines says: \[b^2 = a^2 + c ^2 -2ac*\cos(B)\]

OpenStudy (eyust707):

mine are labeled a little different but i promise it will still work.

OpenStudy (eyust707):

The way I labeled it: B = 17 a = 9 c = 14

OpenStudy (eyust707):

just plug those in and solve for "b"

OpenStudy (anonymous):

how is b 17?

OpenStudy (eyust707):

B is the angle in that corner

OpenStudy (eyust707):

that angle is 17 degrees

OpenStudy (eyust707):

its labeled on the picture...

OpenStudy (anonymous):

a is the angle 17.

OpenStudy (eyust707):

oh gosh let me re do it with their lettering system

OpenStudy (eyust707):

|dw:1422267358858:dw|

OpenStudy (eyust707):

now use this formula: \[a^2 = b^2 + c^2 - 2bc*\cos(A)\]

OpenStudy (eyust707):

we are calling this length "a"|dw:1422267526849:dw|

OpenStudy (eyust707):

just solve for "a" and you are golden

OpenStudy (anonymous):

@eyust707 a=24 right?

OpenStudy (eyust707):

does that seem proportional???

OpenStudy (eyust707):

a should be the smallest length

OpenStudy (eyust707):

a^2 = 9^2 + 14^2 - 2 * 9 * 14 * cos (17)

OpenStudy (eyust707):

first find everything on the right side of that equation

OpenStudy (eyust707):

you literally can google that or type it directly into your calculator

OpenStudy (anonymous):

i did.

OpenStudy (eyust707):

make sure the angle is in degrees not radians

OpenStudy (eyust707):

but thats what a^2 is equal to.. so take a sqrt and youre done

OpenStudy (anonymous):

@eyust707 a=6. you were right before i was using radians.

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