Mathematics
19 Online
OpenStudy (anonymous):
find measurement indicated.
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OpenStudy (anonymous):
OpenStudy (eyust707):
When given a non-right triangle, two sides and one angle the easiest approach to use to find a missing side is the law of cosines
OpenStudy (anonymous):
but i only have one angle if i had two it would be easier.
OpenStudy (eyust707):
|dw:1422266958866:dw|
OpenStudy (eyust707):
In this case we want "b" right?
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OpenStudy (eyust707):
well the law of cosines says:
\[b^2 = a^2 + c ^2 -2ac*\cos(B)\]
OpenStudy (eyust707):
mine are labeled a little different but i promise it will still work.
OpenStudy (eyust707):
The way I labeled it:
B = 17
a = 9
c = 14
OpenStudy (eyust707):
just plug those in and solve for "b"
OpenStudy (anonymous):
how is b 17?
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OpenStudy (eyust707):
B is the angle in that corner
OpenStudy (eyust707):
that angle is 17 degrees
OpenStudy (eyust707):
its labeled on the picture...
OpenStudy (anonymous):
a is the angle 17.
OpenStudy (eyust707):
oh gosh let me re do it with their lettering system
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OpenStudy (eyust707):
|dw:1422267358858:dw|
OpenStudy (eyust707):
now use this formula:
\[a^2 = b^2 + c^2 - 2bc*\cos(A)\]
OpenStudy (eyust707):
we are calling this length "a"|dw:1422267526849:dw|
OpenStudy (eyust707):
just solve for "a" and you are golden
OpenStudy (anonymous):
@eyust707 a=24 right?
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OpenStudy (eyust707):
does that seem proportional???
OpenStudy (eyust707):
a should be the smallest length
OpenStudy (eyust707):
a^2 = 9^2 + 14^2 - 2 * 9 * 14 * cos (17)
OpenStudy (eyust707):
first find everything on the right side of that equation
OpenStudy (eyust707):
you literally can google that or type it directly into your calculator
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OpenStudy (anonymous):
i did.
OpenStudy (eyust707):
make sure the angle is in degrees not radians
OpenStudy (eyust707):
but thats what a^2 is equal to.. so take a sqrt and youre done
OpenStudy (anonymous):
@eyust707 a=6.
you were right before i was using radians.