Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

polynomials will medal

OpenStudy (anonymous):

question up momentarily

OpenStudy (anonymous):

\[(x ^{2}+12x+36) \div (x+6)\]

OpenStudy (anonymous):

@amistre64

OpenStudy (misty1212):

HI!!

OpenStudy (misty1212):

if you are lucky you do not have to do any division factor and cancel works for this, so you are lucky!!

OpenStudy (misty1212):

do you know how to factor \(x^2+12x+36\)?

OpenStudy (anonymous):

im doing something wrong im so bad at division

OpenStudy (misty1212):

no no don't divide

OpenStudy (misty1212):

factor and cancel

OpenStudy (anonymous):

okay what am i supposed to do this is so confusing

OpenStudy (misty1212):

do you know what i mean by "factor"?

OpenStudy (misty1212):

you can factor \[x^2+12x+36\]

OpenStudy (anonymous):

i dont understand

OpenStudy (misty1212):

ok then i will show you

OpenStudy (anonymous):

okay cool thanks

OpenStudy (misty1212):

\[x^2+12x+36\] is perfect square it factors as \[x^2+12x+36=(x+6)(x+6)=(x+6)^2\] factor means to write it as a product (multiplication)

OpenStudy (misty1212):

you can check it is right by multiplying but in any case once you factor, dividing is the same as cancelling \[\frac{(x+6)(x+6)}{x+6}=\frac{\cancel{(x+6})(x+6)}{\cancel{x+6}}=x+6\]

OpenStudy (misty1212):

they say "divide" but they should really say "factor and cancel"

OpenStudy (anonymous):

okay i get it sorta now like it makes sense its just i feel like i cant grasp any of the information

OpenStudy (misty1212):

probably because the instructions are misleading

OpenStudy (anonymous):

yea i dont know because im usually very good at math and if i need help it just means i need a different explanation and im good but this is just confusing

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!