So i need some help answering this question... How many solutions does this system of equations have? -x + 2y = 6 -x + 2y = 0 A. none B. exactly one C. exactly two D. infinitely many
@swissgirl
B
You are given that \(\large\color{blue}{ -x + 2y }\) is equivalent to \(\large\color{blue}{ 6 }\) (based on equation 1), And you are given that \(\large\color{blue}{ -x + 2y }\) is equivalent to \(\large\color{blue}{ 0 }\) (based on equation 2). if one number is equal to \(\large\color{blue}{ 6 }\) and to \(\large\color{blue}{ 0}\) (at the same time), is there such a number ?
(if you have nay questions, ask)
Ok, thanks :D how did you find it?? @rileyreid1998
would that mean that there are none?
it is not D.
@SolomonZelman
are you sure there are infinity of numbers that are equivalent to 6 and to 0 (at the same time) ?
yes.
there is no number that is equivalent to 0 and to 6 at once.
(You can say it is \(\large\color{slate}{\displaystyle \int 0~~dx}\) jk)
Is that the same thing as none? I said A. none.
so its A?
What I said at last with that was a joke, it was in parenthesis. but yes, the answer is A.
yes
Im sorry things keep loading at the wrong times and stuff so it seems like im really confused but im not now XD thankyou@@
I am also confused, my replies got all mixed up. This is the record glitch on OS< or at least one of them. Have a good one, ... bye, and yw
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