Question

Sequence help. *question attached below* Will give medal

Answer 1

Can someone explain to me how I should go about solving this problem? I'm clueless as to where to start

Answer 2

You're supposed to get that quadratic form from the fact that (since the limit exists)
\[\begin{align*}\lim_{n\to\infty}x_n&=\lim_{n\to\infty}x_{n+1}=L\\
L&=\lim_{n\to\infty}\sqrt{5+x_n}\\
L&=\sqrt{5+L}
\end{align*}\]

Answer 3

Hmm, can you explain the steps?

Answer 4

@SithsAndGiggles

Answer 5

oh i was going to write exactly what @SithsAndGiggles wrote

Answer 6

Can you explain the steps so I could understand?

Answer 7

where he saw \(x_n\) and \(x_{n+1}\) he replaced it by \(L\)

Answer 8

that gives \[L=\sqrt{5+L}\]

Answer 9

@satellite73 i have questions about the ambassador program please add me :)

Answer 10

Thank you! @SithsAndGiggles and @satellite73

Answer 11

I still don't think I quite understand how it's equal to l^2-l-5=0