Question

Is this correct? pH Level

Answer 1

\[2.7=-10\log(H^+)\]

Answer 2

so \[*.27=\log(H^+)\] which makes \[H^+=10^{-.27}\] whatever that is

Answer 3

oops decimal in the wrong place!!

Answer 4

\[H^+=10^{-2.7}\]

Answer 5

i do not get the same thing you got
http://www.wolframalpha.com/input/?i=10^%28-2.7%29

Answer 6

http://imgur.com/gallery/AO2egdR