HELP FOR MEDAL!! @misty1212 In Honolulu, Hawaii, the forecast for the next three days is for high temperatures of 80°, 81°, and 80°. 1st objective: What would the temperature on the fourth day need to be to have a 4-day average of °87? 2nd objective: The perimeter of the Hawaiian island of Oahu is approximately 230 miles. If the island were a rectangle with a length that is 35 miles longer than its width, write a system of two-variable equations that you could use to find its length. 3rd objective: Solve the system of equations using substitution or linear combination. Show
HI again!!
hi thanks for coming to help me!
no problem!
i guess it would have to be pretty hot to get a four day average of 87 we can solve it by calling it \(x\), taking the average\[\frac{80+81+80+x}{4}\] and setting it equal to \(87\) to see what we get
in other words, solve \[\frac{80+81+80+x}{4}=87\] first add all that stuff
i get \[\frac{241+x}{4}=87\] so multiply by \(4\) and get \[284+x=348\]
subtract and you are done
is x 64 @misty1212?
i doubt it
what is \(348-241\)?
107?
oh i see i made a typo sorry
yeah seems hot doesn't it? lets check the answer
compute \[\frac{80+81+80+107}{4}\] and see if you get \(87\)
i do!
ready for number two? The perimeter of the Hawaiian island of Oahu is approximately 230 miles. If the island were a rectangle with a length that is 35 miles longer than its width, write a system of two-variable equations that you could use to find its length.
yep how do I do that @misty1212?
it wants a system of two equations, so i guess we have to do that
the perimeter is \(2l+2w\) so one equation is \[2l+2w=230\]
then since the length is 35 miles longer than the width, you have \[l=w+35\]
ooops typo the two equations are \[2l+2w=230\\ l=w+35\]
you good with that?
yep, I see it makes sense @misty1212
ok so on to 3rd objective: Solve the system of equations using substitution or linear combination. Show
since we know \(l=w+35\) we can substitute it in to the top equation and turn ' \[2l+2w=230\] in to \[2(w+35)+2w=230\] and solve for \(w\)
here are a few ways to solve this i would start by dividing by 2 to get \[w+35+w=115\] or \[2w+35=115\] and solve that one
hmm w=35 too @misty1212?
oh no never mind it's 40
thanks again for the help @misty1212!
Join our real-time social learning platform and learn together with your friends!