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A particle moves along the x-axis in such a way that its acceleration at time t for t>0 is given by a(t)=3/t^2. How do I find an equation for the position, x(t) of the particle for all t>0?
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if the equation of position is X(t), then the equation of the velocity is V= X'(t) and the equation for acceleration is A(t) = V'(t) = X"(t) so that, if you are given A(t) , then take integral once to get V and then one more time to get X
I got that v was -3/t. I'm having trouble finding the antiderivative of that
hehehe we may forget (ln t)' = 1/t
oh!!! thank you!
yw
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