How would you have (w+1)^5 power be a polynomial? I know it would be a^5+5(a^4)(b)+10(a^3)(b^2)+10(a^2)(b^3)+5a(b^4)+(b^5)?
HI!!
you mean you want to expand it?
yes we are learning about binomials
I'm awfully confused, if its 5*(1^4) would it be 5^4?? right?
yes
\[w^5+5w^4\] is the first two terms you can get all the coefficients from pascal's triangle
you know the numbers from the fifth row of pascal's triangle?
ok then so i got so far w5+5w4+5 would it be correct?
and yes we wrote them down, I was given 1, 5, 10, 10, 5, 1
ok good
then since one to any power is just one, keep dropping the power on the \(w\) by 1 is all
\[w^5+5w^4+10w^3+...\]
you can finish it only two more to go
ok then, I had to add the numbers so my answer is 2^5+25^4+20^3+20^2+10 is this correct?
no dear it is not with numbers this is your question \[(w+1)^5\]right :
yes so we don't add the numbers??? ok then so sorry so we just keep the letters
so it's w5+5w4+10w3+10w2+10 then?
ooh so close
\[w^5+5w^4+10w^3+10w^2\] all that is right but you missed the last two
remember it goes \[1,5,10,10,5,1\]
wait so w5+5w4+10w3+10w2+5w+10?
ooooh again sooooo close missed the last one though...
darn umm then I'm stuck
no you aren't what is \(1\times 1^5\)?
let me know when you get \(1\) i am not sure how you ended with that ten !!
wait so w5+5w4+10w3+10w2+5w+1^5
whew so now, just so your teacher does not think you are a bit daft now to know that \(1^5=1\) please rewrite it as \[ w5+5w4+10w3+10w2+5w+1\]
oh ok then thank you much!!!
\[\color\magenta\heartsuit\]
Join our real-time social learning platform and learn together with your friends!