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OpenStudy (misty1212):
ok lets go back up slowly q
OpenStudy (misty1212):
we got \[\sqrt{2x+13}=x+5\]
when you square the left, you just get \(2x+13\)
OpenStudy (misty1212):
in other words, the radical goes bye bye
that is the whole point
OpenStudy (misty1212):
so we get
\[2x+13=(x+5)^2\] as the next step
OpenStudy (anonymous):
Oh okay! I see. then \[x ^{2}+25\]
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OpenStudy (anonymous):
or no?
OpenStudy (misty1212):
oooh no don't make that mistake or your teacher will think you are a moron
you don't want that !
OpenStudy (anonymous):
lol.. okay.. then what do i do?
OpenStudy (misty1212):
\[(x+5)^2=(x+5)(x+5)=x^2+5x+5x+25=x^2+10x+25\]
OpenStudy (anonymous):
wait what?
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OpenStudy (misty1212):
square means multiply by itself
OpenStudy (misty1212):
some teachers like to call that "foil" maybe you heard it that way
OpenStudy (anonymous):
yeah, and x * x is x^2? and 5*5 is 25? i thought...
OpenStudy (misty1212):
yea i know what you thought
you thought you could square each piece separately
OpenStudy (misty1212):
and yes, there is an \(x^2\) in the answer, as well as a \(25\) but it is not
\[(x+5)^2=x^2+25\] like i said DO NOT MAKE THAT MISTAKE
it is \((x+5)^2=x^2+10x+25\)
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OpenStudy (anonymous):
okay. now what?
OpenStudy (misty1212):
ok now it has been so long we start at the top and go quicker
\[\sqrt{2x+13} - 5 = x\] add 5\[\sqrt{2x+13}=x+5\] square (correctly)\[2x+13=x^2+10x+25\] now you have a quadratic equation to solve
OpenStudy (misty1212):
subtract \(2x\) and \(13\) to set it equal to zero, get
\[x^2+8x+12=0\] and now solve for \(x\) by factoring if you can
OpenStudy (anonymous):
\[8x^{2}=-12?\]
OpenStudy (anonymous):
or no?
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OpenStudy (misty1212):
no
OpenStudy (anonymous):
or \[x^{2} + 8x=-12\]
OpenStudy (anonymous):
oh no?
OpenStudy (misty1212):
do you know how to factor?
OpenStudy (anonymous):
No. :/
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OpenStudy (misty1212):
hmm that is a problem
because you really want to turn \[x^2+8x+12=0\] in to
\[(x+2)(x+6)=0\]
OpenStudy (anonymous):
How did you get 2 and 6?
OpenStudy (misty1212):
have you spent any time solving quadratic equations ?
OpenStudy (misty1212):
i got them because \(2\times 6=12\) and \(2+6=8\)
OpenStudy (anonymous):
No, I missed 3 years of highschool because I had lynch syndrome(cancer), I was NEVER there to learn anything. I am pretty much teaching myself through the course of online schooling just trying to pass and get to college. and I see. So you find two numbers that can go into both of them?
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OpenStudy (misty1212):
two numbers whose product is 12 and whose sum is 8 yes
OpenStudy (anonymous):
okay, i understand. so then do we do that foil thing you talked about?
OpenStudy (misty1212):
now that we have \[(x+2)(x+6)=0\] we solve
\[x+2=0\] and get \(x=-2\) and also \(x+6=0\) to get \(x=-6\)
OpenStudy (misty1212):
then we go back to the original equation and try them out
OpenStudy (anonymous):
okay, I see. so we plug it in?
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OpenStudy (anonymous):
\[\sqrt{2(-2)+13}-5=-6\]
OpenStudy (anonymous):
?
OpenStudy (misty1212):
yes \[\sqrt{2x+13}-5=x\]
\[\sqrt{2\times (-2)+13}-5=-2\] true for faclse
OpenStudy (anonymous):
false? Shouldnt it be =-6?
OpenStudy (misty1212):
the right sides should be \(-2\) because it is x
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OpenStudy (misty1212):
we will try \(-6\) second
OpenStudy (anonymous):
okay
OpenStudy (misty1212):
now we are trying \(x=-2\) which means everywhere
OpenStudy (anonymous):
okay I see. so \[\sqrt{2(-2)+13}-5=-2\]
OpenStudy (misty1212):
\[\sqrt{2\times (-2)+13}-5=-2\] works because you get
\[\sqrt{-4+13}-5=\sqrt{9}-5=3-5=-2\checkmark\]
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OpenStudy (anonymous):
Okay, so is that all we do?
OpenStudy (misty1212):
no, now we try \(x=-6\) to see if that works
OpenStudy (misty1212):
\[\sqrt{2(-6)+13}-5=-6?\]
OpenStudy (anonymous):
\[\sqrt{-12+13} -5=-6\]
OpenStudy (misty1212):
this one does not work
we get
\[\sqrt{1}-5=1-5=-4\neq -6\]
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OpenStudy (anonymous):
so it would be -2?
OpenStudy (misty1212):
whew yes, after all that
OpenStudy (misty1212):
so lets see what we needed to do this
a) a method
b) knowing how to square correctly
c) solving a quadratic equation
d) knowing to check the answer
OpenStudy (anonymous):
So that is the final answer?
OpenStudy (misty1212):
yes final answer is -2
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OpenStudy (anonymous):
Thank you soooo much.
OpenStudy (misty1212):
i would suggest that the other stuff is somewhat more important than this
but no matter you do what you have to
your welcome \(\color\magenta\heartsuit\)