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I HAVE A FINAL TOMORROW, PLEASE HELP ME Simplify: 7i^2-i^3
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Is it i as in \( \sqrt{-1}\)?
isn't I -1??????????????????
No \[i=\sqrt{-1}\]
oh sorry LOL I thought you said i^2
and yeah, you're right
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so, how do you do this?
ok i^2=-1 and \[i^3=\sqrt{i*i*i}=\sqrt{i^2*i}=-1\sqrt{-1}=-1i\]
UHHHHHHHHHHHH the answer is 7+i
hmmmm 7i-i=7(-1)-(-1i)=??? Watch ur signs
lol sorry the problem is 7i^4 not 7i^2
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sorry
Ok gotcha lol
ok well i get how to get the 7 cause -1 * -1 is a positive, but I still don't get the the i is a positive as well you said it was -1i
nah cuz look 7(1)-(-1i)=7+i
OHHHHHHHHHHHHHHHHHHHHHHH OK, I GET IT THANK-YOU SO MUCH
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7i^2-i^3 factor = i^2(7-i) use i^2=-1 = -(7-i) = -7+i
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