Question

Given the function f(x) = 4x - 16, what is the x-value of the locator point of f-1(x)?

Answer 1

is the locator point, where the curves f(x) and the inverse intersect...?

Answer 2

don't really know

Answer 3

Do it like this.
Y= 4x-16
16=4x
16/4=x
4=x value of x

Answer 4

Is this what you are looking for ?

Answer 5

is that how you are suppose to do the problem?

Answer 6

its suppose to be 4^x not 4x, I messed that up

Answer 7

Is it possible if you rewrite your equation?

Answer 8

Given the function f(x) = 4^x - 16, what is the x-value of the locator point of f^-1 (x)?

Answer 9

well the inverse function is

\[f(x) = \frac{ x + 16}{4}\]

ok, doing some reading the locator point for a linear function is the y- intercept...

so the y- intercept has coordinates (0, a) where y = a is the intercept...

so the x value of the inverse is x = 0

that's my best guess

here is a clipping of some notes I found

Answer 10

It is kind of based on common sense.

Answer 11

so find the inverse of

\[y = 4^x - 16\]

Answer 12

Y= 4^x -16
16= 4^x

Answer 13

In here the value of x is 2

Answer 14

4^2=16

Answer 15

I hope I answered your question.

Answer 16

oh ok thank you for making the problem clear to understand

Answer 17

No problem. :)