simplify the rational expression state any excluded values x^2-x-6/x+2
Factor the trinomial and it becomes another easy one :)
Help
I really dont get it. Its my nephews algebra. I have no idea what to do.
x^2-x-6 To factor trinomials (this is worth remembering), find 2 numbers that equal -1 when added and -6 when being multiplied
Still confused
Quadratics are set up as ax^2+bx+c as long as the value of a is one, you can say that the answer or roots for a quadratic. Is 2 numbers that add up to the value of b, and multiply to the value of c. x^2-x-6 Think. What two numbers add up to -1 but multiply to -6 (together)
Still cant get it. Im sorry im just dumb.
Don't say that. Example: x^2+4x+4 I have to find two numbers that add up to 4, but multiply to 4 as well. That is simply 2,2 as the numbers (2,2) add up to 4 and multiply to 4.
Try one more time
You can do it
Im not understanding what your saying.
Wait... -2?
If I asked you for two numbers that add up to 10, but multiply to 25, could you do it?
5?
Exactly, 5 and 5.
x^2-x-6 What two numbers add up to -1 but multiply to -6 (together) Same logic, don't make it hard
-3
That's one of the numbers, what's the other one?
3
two numbers add up to -1 but multiply to -6 3+(-3)=0 3 x -3=-9 that wouldn't work..
Wait.... no -2
Let's see -3,-2 -3+-2=-5 -3 x -2=6 There is a small error with -2
So just 2
Yes!! -3,2 are the factors of x^-x-6 Which can be expressed as (x-3)(x+2)
Now onto your question..\[\frac{ (x-3)(x+2) }{ (x+2) }\]
What terms can you cross out?
X+2
Exactly so your just left with x-3, the simplified rational expression of your question
That took a while but I hope you have a better hint on quadratic factoring now. It's vital in algebra :O
So the answer is just x-3
yep
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