Question

Consider the curve given by x2 + sin(xy) + 3y2 = C, where C is a constant. The point (1, 1) lies on this curve. Use the tangent line approximation to approximate the y-coordinate when x = 1.01.

Answer 1

@Zale101

Answer 2

@perl

Answer 3

dy/dx[x cos(xy) + 6y] = -2x - y cos(xy)

Answer 4

dy/dx = -[2x + ycos(xy)]/[xcos(xy) + 6y]

Answer 5

do you know what to do from there?

Answer 6

@NathanJHW

Answer 7

no sorry

Answer 8

I think the answer might be 0.996 but I'm not sure.

Answer 9

@Daniellelovee

Answer 10

you are correct

Answer 11

awesome!

Answer 12

are you able to help me with anymore problems?

Answer 13

idk depends on the tutorials online because I'm not a calculus student yet

Answer 14

well can you try this one please?

Answer 15

The graph of y = x6 + 4.5x5 − 10x4 + 5x − 10 is concave upward for all values of x such that:

Answer 16

ok

Answer 17

yeah I have no idea sorry -.-'

Answer 18

that's ok lol

Answer 19

perhaps this one?

Answer 20

ok (keep in mind I'm still in algebra 2 lol this is too advanced)

Answer 21

oh alright then

Answer 22

I'll just figure them out myself

Answer 23

thank you for your help!

Answer 24

good luck because I spent like 30 mins watching a tutorial for the last one XD
but hey at least I have a base for when I start calculus :P :)
and np but Im sure that the first one is 0.996

Answer 25

try @ganeshie8 and @Directrix they usually help :)