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Chemistry 15 Online
OpenStudy (bhumi273):

a 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096g of boron and 0.1444g of oxygen. calculate the % composition of compound by wieght. help.... medal...

OpenStudy (alekos):

there's something not quite right about the question

OpenStudy (alekos):

% composition of compound by weight doesnt make sense to me

OpenStudy (bhumi273):

hmnm.. ya.. its 0.144g of oxygen

OpenStudy (alekos):

can you send me a screen shot of the question?

OpenStudy (mrnood):

so - this is a simple calculation of % total compound weight is 0.24g weight of Oxygen is 0.144g what % of 0.24 is 0.144? for Boron weight of Boronis 0.096g what % of 0.24 is 0.096?

OpenStudy (alekos):

it could simply be Boron .096/.24 x 100 % and the same method for O2

OpenStudy (alekos):

Like Mr Nood has done

OpenStudy (alekos):

and perl

OpenStudy (mrnood):

@perl It is not allowed by CoC of the site to give answers. The method was described above. You should let the OP DO some work for themselves

OpenStudy (perl):

I gave the calculation, not the answer

OpenStudy (perl):

but i will remove it :)

OpenStudy (mrnood):

once the numbers are in the formula it requires no thought from the OP to solve.

OpenStudy (bhumi273):

ok.. thnx ppl... can u plzz help me wid othr q n a

OpenStudy (bhumi273):

so.. nxt one, when 3g of carbon is burnt in 8g of oxygen 11g of carbon di oxide is produced. find the mass of carbon di oxide produced on burning 3g of carbon in 50g of oxygen.

OpenStudy (perl):

i would first make a balanced equation

OpenStudy (perl):

first balance the equation C + O -> CO2

OpenStudy (anonymous):

Sorry I cant help :( Gooduck to everyone trying to figure it out though!

OpenStudy (bhumi273):

ok..... :( plzz.. .any1...

OpenStudy (mrnood):

I THINK (but you need to check!) Since in th efirst case the resultant mass of CO2 + 3+8 it means that ALL the Carbon and ALL the oxygen are combined in the CO2 SO if you add MORE oxygen there is no mor carbon left to combine - so you cannot make MORE CO2 than in the first case.....

OpenStudy (bhumi273):

ok........

OpenStudy (anonymous):

just i am triying

OpenStudy (bhumi273):

so nxt 1... 1)if the valency of an element A is 3, write the chemical formula of its oxide. 2)if an element X has valency 2, then write the chemical formulation of potassium salt. 3)write the valency of potassium ion, and write the chemical formula of chemical phosphate.

OpenStudy (anonymous):

so what is the valency of oxygen

OpenStudy (anonymous):

u there

OpenStudy (anonymous):

no 2

OpenStudy (bhumi273):

ok

OpenStudy (anonymous):

so we just transfer the valency of both

OpenStudy (bhumi273):

.... thn.....

OpenStudy (anonymous):

u say

OpenStudy (anonymous):

then we have X2O3

OpenStudy (bhumi273):

idk

OpenStudy (anonymous):

okay we have X 2 O 3

OpenStudy (bhumi273):

k..

OpenStudy (anonymous):

then next one u try it

OpenStudy (bhumi273):

i dont know yaar.. plzz do it for me.. plzz

OpenStudy (anonymous):

nah but u try it once

OpenStudy (bhumi273):

i dont actually know yaa

OpenStudy (anonymous):

what is the valency of potassium

OpenStudy (anonymous):

search it and say

OpenStudy (bhumi273):

i guess 1

OpenStudy (anonymous):

yes then what is the valency of X

OpenStudy (bhumi273):

2

OpenStudy (anonymous):

yes so exchange them

OpenStudy (bhumi273):

ok.. so, 1X & 2K

OpenStudy (anonymous):

nah ur correct but we write it as X small 1 and K small 2

OpenStudy (bhumi273):

ok..

OpenStudy (anonymous):

1and 2 are small

OpenStudy (bhumi273):

i hav still many questions to ask....

OpenStudy (bhumi273):

compute the no. of sodium ions present in 5.85g of sodium chloride.

OpenStudy (anonymous):

wait wait I need some reaserch

OpenStudy (bhumi273):

ok..

OpenStudy (anonymous):

So, in 1 g of NaCl, number of sodium ions= 6.023* 1023 / 58.5. So in 5.85 g of NaCl, number of sodium ions= ...

OpenStudy (anonymous):

calculate now

OpenStudy (anonymous):

u can do it now :)

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