Question

1)convert 12.043010^22 molecules of sulphur dioxide in moles.
2)out following whch has more no. of atoms: 50g of Cu or 50g of Fe.
calculate:
a) the mass of 1.0505010^23 molecules of carbon dioxide.
b) the no. of molecules of 0.25 moles of ammonia.
c) the formula unit mass of sodium sulphite.
3)calculate the following quantities in 5.6g of nitrogen:
a) no. of moles in N2.
b) no. of molecules of N2.
c) no. of atoms of nitrogen.
4)calculate the no. of al ions in 0.051g of Al2O3. atomic mass of Al=27u, O= 16u
5)how many Ag atoms are there in 0.0001g of Ag? molar mass of Ag is 108g/mole

Answer 1

@shereenkhan @TheRaggedyDoctor @Angel_Bear19 @AaronAndyson @SyedMohammed98 @syay43 @showa @Darknight200 @dan815 @ganeshie8 @Jessica3tbc @KittyT @Krinkov @ziqbal103 @xo.minnie.xox @Callisto @cookiemonster2412 @comso1 @mathslover @mustafa2014

Answer 2

wow need time to do this

Answer 3

its ok... but a bit faster
wid worked out solution.. plz...

Answer 4

*medal*

Answer 5

@paki

Answer 6

number of molecules and divide by Avogadro's number is mole.... do it....

Answer 7

ok.. thn... d othrs

Answer 8

for 3rd one... have a look here...

http://www.meritnation.com/ask-answer/question/calculate-the-following-quantities-in-5-6-g-of-nitrogen-gas/atoms-and-molecules/6678871

Answer 9

ok.... thn.....

Answer 10

@bhumi273 do you know how to do this?

Answer 11

nah

Answer 12

lol I dont either. I took chemistry but it never stuck with me.

Answer 13

oh.... :(

Answer 14

But that doesn't mean I won't try. :) I'm not leaving until we figure this thing out okay?

Answer 15

okay...

Answer 16

Okay I do remember moles. Do you know the formula for moles? That would help

Answer 17

For 5th part divide 0.000
1 with molar mass that is.....0.0001/108 .once u get the answer ..multiply the nswer with avagadras constant .ur will het the number of atoms
"

Answer 18

ok..

Answer 19

for 3rd part. a) mass of N2 divided by relative atomic mass( nitorgen= 14)

Answer 20

....

Answer 21

for b) times with avagdro's constant

Answer 22

......

Answer 23

why am i wrong?

Answer 24

no....

Answer 25

2 & 4

Answer 26

?????