Question

find the slope of a line that is perpendicular to the lie containing the points (-2,-1) and (2,-3).

Answer 1

do you know the equation to find the slope?

Answer 2

do I multiply -3 time -1?

Answer 3

m= y2-y1
-----
x2-x1
that is the formula to find the slope

Answer 4

I don't really understand the process of working out this problem

Answer 5

okay hold on, i will explain

Answer 6

first you need to find the slope of the the two given points (-2,-1) (2,-3)

Answer 7

Do so by using the formula m= y2-y1 / x2-x1

Answer 8

@bibby I don't understand

Answer 9

my answer was negative 4

Answer 10

find the slope, recall that perpendicular lines have slopes that are negative reciprocals of the original slopes

just follow what Quxxn is saying

Answer 11

but wont it be -1

Answer 12

-2/4 sorry i wrote the wrong answer

Answer 13

so my anwer would be -1/2

Answer 14

\((-2,-1) and (2,-3).\huge\longrightarrow\frac{-3--1}{2--2}=\frac{-3+1}{2+2}=\frac{-2}{4}\)

Answer 15

yes, that is the slope of your first equation

Answer 16

the original m is now -1/2

what would the perpendicular lines slope be?

Answer 17

-1?

Answer 18

"recall that perpendicular lines have slopes that are negative reciprocals of the original slopes"

Answer 19

why did you change your picture I thought you were a girl

Answer 20

rofl, I'm anything you want me to be

Answer 21

wait so whats the anwer then we can chit chat

Answer 22

either way, reciprocals are defined as \(\large a \longrightarrow \frac{1}{a}\)
so the negative reciprocal of (let's take a random number) 3 is \(\large -\frac{1}{3}\)

Answer 23

find the negative reciprocal of the original lines slope