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OpenStudy (anonymous):
Algebra 2 help, please?
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OpenStudy (anonymous):
\[If f(x)=3x+1 and f ^{-1}=\frac{ x-1 }{ 3 } then f ^{-1}(7)=\]
OpenStudy (dtan5457):
You would just plug 7 as the x value of (f)^-1
OpenStudy (dtan5457):
You already have the inverse of f(x), they want f(^-1)(7)
OpenStudy (anonymous):
A.) 22
B.) 2
C.) -2
OpenStudy (dtan5457):
Did you try plugging 7 into the inverse function? It becomes straight forward once you do
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OpenStudy (anonymous):
I don't know how to do these equations.
OpenStudy (anonymous):
I still don't get it..lol
OpenStudy (dtan5457):
I had a typo it's \[f^{-1}(7)=\frac{ (7)-1 }{ 3 }, or \frac{ 6 }{ 3 }\]
OpenStudy (dtan5457):
6/3 is the most simplified way i can possibly explain it to you
OpenStudy (dtan5457):
6/3=?
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OpenStudy (anonymous):
\[if f(x)=3x+1 and f ^{-1}=\frac{ x-1 }{ 3 } then the ordered pair of ƒ(3) = (3, 10) (3, 2/3) (10, 3)\]
OpenStudy (dtan5457):
Can you screen shot? your question is cut off., don't write words into equation form lol
OpenStudy (anonymous):
I'm on my laptop..lol
OpenStudy (dtan5457):
i can't understand your question lol
laptops can take screenshots too
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