simplify to standard form:
-i (-4 + 2i) (6 - 7i) + 3
step by step

Question

simplify to standard form:
-i (-4 + 2i) (6 - 7i) + 3
step by step

misty1212 · Answer

HI!!

misty1212 · Answer

do you know $i^2=-1$?

anonymous · Answer

misty! :D and noo ive forgotten a lot of things with math

misty1212 · Answer

ok well it is true, $i^2=-1$ lets take it one step at a time

misty1212 · Answer

lets first compute 
$$-i(-4+2i)$$using the distributive law and see what we get 
as a first step it$$4i-2i^2$$ right?

misty1212 · Answer

this is where you say "yes, that is what you get when you distribute"

anonymous · Answer

lol!! I was looking at the equation to make sure and yes, that is what you get when you distribute

misty1212 · Answer

ok and then we recall that $i^2=-1$ so what is this really?

anonymous · Answer

my mind is in blank no lie :$

misty1212 · Answer

what is $-2i^2$ if $i^2=-1$

anonymous · Answer

I multiply -2 to -2 right?

misty1212 · Answer

ahh nvm it is $+2$ so you have 
$$(2+4i)(6-7i)+3$$

anonymous · Answer

okay so quick question so I wont forget and keep sounding dumb, whenever theres a lets say - i  what can i replace it for?

misty1212 · Answer

nothing

misty1212 · Answer

$-i=-i$ just leave it

anonymous · Answer

alright thanks I understood it a little bit more especially the positive 2 part

misty1212 · Answer

your next job is $$(2+4i)(6-7i)$$

anonymous · Answer

6i -1i + 3? would it be something like that?