You invest $2,000 in an account that has an annual interest rate of 3.2%, compounded annually. How much money will be in the account after 12 years? Round your answer to the nearest whole number.
Does this use the formula A=P(1+r)/nt ?
yep
\[A = P(1+\frac{ r }{ n })^{nt}\] P = principal amount (the initial amount you borrow or deposit) r = annual rate of interest (as a decimal) t = number of years the amount is deposited or borrowed for. A = amount of money accumulated after n years, including interest. n = number of times the interest is compounded per year
your problem is compounded so it is actually the formula above :)
@onelove26 let me know if you need more help
(where t = 1, because it's compounded annually = once a year)
@mg_omg yes :)
wheer n = 1 , t = 15
sorry t = 12
so, @kl0723 the equation would be: A=2,000(1+3.2/12)^1*12 Is that correct? or am I wrong?
is right but remeber the rate has to be in decimal form, you have it in percentage
to get the percentage in decimal form just divide the value by 100
which then I will get: .032
So how will I exactly go about solving this?
that is 0.032
okay. but how will I exactly go about solving this type of equation? @kl0723
just solve for A, you have all the values you need to do so
should I divide .032 by 12 first??
@kl0723
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