Question

How do I find the value of (-16)^1/4?

Answer 1

You can google this stuff ya know, google is a calculator as well as many other things

Answer 2

My answer is wrong. Btw. The answer is sqrt 2 + sqrt 2i

My bad.

Answer 3

its -4

Answer 4

No, it's not. :) The fourth root of a negative number must contain i.

Answer 5

its -2

Answer 6

No it's not. It's sqrt 2 + sqrt 2i

Google "Fourth root of -16" :)

Answer 7

-16^0.25

Answer 8

http://www.wolframalpha.com/input/?i=%28-16%29%5E1%2F4%3F

Answer 9

Stop googling for answers, if you don't know how to give them in proper syntax @VectorPrime :)

Answer 10

I suck at math btw, dont trust my answers on here

Answer 11

so whats the answer @ApoorvaAnand

Answer 12

\(\Large {
\bf a^{\frac{{\color{blue} n}}{{\color{red} m}}} \implies \sqrt[{\color{red} m}]{a^{\color{blue} n}}\qquad thus
\\ \quad \\
(-16)^{\frac{{\color{blue}{ 1}}}{{\color{red}{ 4}}}}\implies \sqrt[{\color{red}{ 4}}]{-16^{\color{blue}{ 1}}}
}\)

Answer 13

any ideas on simplifying 16 to an value with an exponent?

Answer 14

but wouldn't it be 16i

Answer 15

well... sorta, not quite
if you leave it at as 16... it'd be then .. one sec

Answer 16

would it be 2 + sqrt(i)

Answer 17

one sec

Answer 18

I assume you don't have any choices?

Answer 19

no i dont sorry

Answer 20

I can make out this much thus far \(\bf \large {
(-16)^{\frac{{\color{blue}{ 1}}}{{\color{red}{ 4}}}}\implies \sqrt[{\color{red}{ 4}}]{-16^{\color{blue}{ 1}}}\implies \sqrt[4]{-1\cdot 16}\implies \sqrt[4]{-1}\cdot \sqrt[4]{16}
\\ \quad \\
\sqrt[4]{-1}\cdot \sqrt[4]{2^4}\implies 2\sqrt[4]{-1}
}\)

Answer 21

oh ok thnx, i got it cx

Answer 22

yw

Answer 23

isnt 4radical(-1) the same as i^4

Answer 24

@jdoe0001