An object is launched upward at 64 ft/sec from a platform that is 80 feet high. What is the objects maximum height if the equation of height (h) in terms of time (t) of the object is given by h(t) = -16t2 + 64t + 80?

A)144 feet
B)123 feet
C)167 feet
D)172 feet

Question

An object is launched upward at 64 ft/sec from a platform that is 80 feet high. What is the objects maximum height if the equation of height (h) in terms of time (t) of the object is given by h(t) = -16t2 + 64t + 80?
 
       A)144 feet
        B)123 feet
        C)167 feet
        D)172 feet

alekos · Answer

have you attempted this?

kl0723 · Answer

max would be at vertex, how do you find the vertex?

anonymous · Answer

I attempted and got lost.

kl0723 · Answer

we need to find the vertex, -b/2a do you remeber this?

alekos · Answer

h(t) is an inverted parabola which describes the path of the object

kl0723 · Answer

|dw:1422500546454:dw|

zale101 · Answer

h(t) = -16t^2 + 64t + 80 is your position equation. You are looking at the maximum height. In a quadratic equation, a max height would look like|dw:1422500571626:dw|