Permutation and Combination problem

Question

dumbsearch2 · Answer

My teach wrote this to me when I asked a question about my assignment:

"The calculations should be done for each position. For example, if you choose 3 players for the pitcher position, the combination would be 3C1 for that position. 3! / 1!(3-1)!. This is the format to follow for each position for both combinations and permutations. Once each is calculated, the results are multiplied to get the final combination or permutation answer."

dumbsearch2 · Answer

But I'm confused- isn't 3C1 just 3? Could someone explain this to me?

dumbsearch2 · Answer

Do you think my teacher made a mistake when she explained it to me, or do I just not understand what she's saying?

dumbsearch2 · Answer

@perl @ganeshie8

perl · Answer

3 C 1 = 3 , that is correct

perl · Answer

it turns out that 3C1 = 3P1

perl · Answer

From a set of 3 players , you are asked how many ways can you choose 1. since you are only choosing 1, it makes no difference if you say order counts or order does not count.

ABC 

A , B , C

perl · Answer

if you ask how many ways can you choose 2 players from the set of 3 players, now the issue of order of selection does matter

3 C 2 = AB , AC, BC  

3 P 2 = AB, BA, AC, CA, BC, CB

perl · Answer

3 C 1 = A , B, C 

3 P 1 = A, B , C