Question

Jenny, who rides a moped, takes 2 hours less to travel 60 miles than Maureen takes to travel 50 miles on her bicycle. Jenny travels 10 miles per hour faster than Maureen. (Hint: speed = distance ÷ time.)

Answer 1

I just don't know how to plug in what I have.

Answer 2

60x - 50(x-2) = 10x(x-2)
-----------------------
10x + 100 = 10x^2 -20x
10x^2 -30x - 100 = 0
x^2 - 3x - 10 = 0
(x-5)(x+2) = 0
Positive solution::
x = 5
---------------------
Maureen DATA: time = x = 5 hrs ; rate = 50/5 = 10 mph
Jenny DATA: time = x-2 = 3 hrs ; rate = 60/3 = 20 mph
===========================

Answer 3

Maureen's speed = 50 / Jenny's time + 2 hrs.
Jenny's speed = Maureen's speed + 10 miles/hour
Jenny's speed = Maureen's time - 2 hours / 60 miles.

I think that's what you're looking for.

Answer 4

hope it help's .....

Answer 5

Jenny, who rides a moped, takes 2 hours less to travel 60 miles than Maureen takes to travel 50 miles on her bicycle. Jenny travels 10 miles per hour faster than Maureen. (Hint: speed = distance ÷ time.)
-------
Jenny DATA:
distance = 60 miles ; time = x-2 hrs ; rate = d/t = 60/(x-2) mph
-------
Maureen DATA:
distance = 50 miles ; time = x hrs ; rate = 50/x mph
---------------------
Equation:
rate - rate = 10 mph
60/(x-2) - 50/x = 10 mph
-----


60x - 50(x-2) = 10x(x-2)
-----------------------
10x + 100 = 10x^2 -20x
10x^2 -30x - 100 = 0
x^2 - 3x - 10 = 0
(x-5)(x+2) = 0
Positive solution::
x = 5
---------------------
Maureen DATA: time = x = 5 hrs ; rate = 50/5 = 10 mph
Jenny DATA: time = x-2 = 3 hrs ; rate = 60/3 = 20 mph
===========================

Answer 6

@Xd1521 can you explain how you got from the question to your solution, because it sounds like what the person is having problems with is plugging things into the equation, and I'm not sure how you did it there, that might help them out.

Answer 7

where i got from u mean? @PsychoTink

Answer 8

yea that works too.("

Answer 9

ok http://www.algebra.com/algebra/homework/word/travel/Travel_Word_Problems.faq.question.899068.html

Answer 10

does that help at all?

Answer 11

I can google. I see you very clearly got the answer from
http://www.algebra.com/algebra/homework/word/travel/Travel_Word_Problems.faq.question.899068.html

But that doesn't help teach the person who asked this question HOW to solve the problem theirself, where the numbers came from and why.

Answer 12

i know i didnt know the ansewer thts y i googled

Answer 13

easy look their and u can look it up easly .

Answer 14

google is a thing for learn from ...

Answer 15

but just got look for what your look for .

Answer 16

@Icecube902 @YOUNGSUPERMAN

Answer 17

yes

Answer 18

Two things, "google is a thing for learn from ..." is an incorrect sentence and has no meaning.

Second, while you can use Google to find an answer, that does not mean you are learning. Getting an answer and learning are separate things. If you learn how to set up and do the problem then you can easily get answers. Also, being able to translate these types of word problems helps you learn how to do real life applications of math in an assortment of fields. So it is far better to learn the material than just to find an answer.